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Natasha2012 [34]

3 years ago

5

When finding the volume of the volleyball, Erica used 3.14 in the formula. What type of measurement accuracy is used?

1 answer:

Paladinen [302]3 years ago

8 0

Answer:

c

Step-by-step explanation:

you would have to estimate bc you won't get an exact measurement . hope this helpssss. brainliest?

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From a radar station, the angle of elevation of an approaching airplane is 32.5 degree. The horizontal distance between the plan

denis23 [38]

Answer: 42.21 km

Step-by-step explanation:

We can solve this using trigonometry, since we have the following data:

$\theta=32.5\°$ is the the angle of elevation

$d=35.6 km$ is the horizontal distance between the plane and the radar station

$x$ is the hypotenuse of the right triangle formed between the radar station and the airplane

Now, the trigonometric function that will be used is <u>cosine</u>:

$cos\theta=\frac{d}{x}$ because $d$ is the adjacent side of the right triangle

$cos(32.5\°)=\frac{35.6 km}{x}$

Finding $x$ :

$x=\frac{35.6 km}{cos(32.5\°)}$

$x=42.21 km$

4 0

3 years ago

Triangle angle - sum theorem<br> what is the value of y?

dangina [55]

Answer:

y = 5

Step-by-step explanation:

All angle measures in a triangle add up to 180°.

This means that 63 + 82 + 7y = 180

<u>Solving for Y:</u>

Step 1: Combine like terms.

$(7y) + (63+82)=180$
$7y + 145 = 180$

Step 2: Subtract 145 from both sides.

$7y + 145 - 145 = 180 - 145$
$7y = 35$

Step 3: Divide both sides by 7.

$\frac{7y}{7} = \frac{35}{7}$
$y = 5$

Step 4: Check if solution is correct.

$7(5) + 63 + 82 = 180$
$35 + 63 + 82 = 180$
$98 + 82 = 180$
$180 = 180$

Therefore, y = 5.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

3 0

2 years ago

NEW AMONG US CODE<br> YHFZNF

const2013 [10]

Answer:

ok

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Fully simplify 14xy^4(-14y)

alina1380 [7]

The answer would be ~-196xy^5~

Hope this helps

Have a great day/night

5 0

3 years ago

In her metalwork class, Anja cut a square of

Paul [167]

Given:

Anju cut square of tin, of edge 3.7 cm, from a larger square of edge 6.3 cm.

To find:

The area of the remaining tin.

Solution:

Area of a square is:

$Area=a^2$

Where, a is the edge of the square.

Area of the smaller square is:

$A_1=(3.7)^2$

$A_1=13.69$

Area of the larger square is:

$A_2=(6.3)^2$

$A_2=39.69$

The area of the remaining tin is:

$A=A_2-A_1$

$A=39.69-13.69$

$A=26$

Therefore, the area of the remaining tin is 26 sq. cm.

8 0

2 years ago