Literal Equations, p = 144p/y, Solve for p

Jayden has 10 pound bag of flour. He needs to separate the flour into3/5 pound bags. How many bags can he make explain your reas

S_A_V [24]

Answer:

17

Step-by-step explanation:

10 pounds in 3/5 bags means 50/5 bags

50/3 is 16.67, rounded he needs 17 bags

6 0

3 years ago

A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collecte

allsm [11]

Answer:

The degrees of freedom are given by;

$df =n-1= 5-1=4$

The significance level is 0.1 so then the critical value would be given by:

$F_{cric}= 7.779$

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

Step-by-step explanation:

For this case we have the following observed values:

Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100

For this case the expected values for each day are assumed:

$E_i = \frac{100}{5}= 20$

The statsitic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}$

Where O represent the observed values and E the expected values

The degrees of freedom are given by;

$df =n-1= 5-1=4$

The significance level is 0.1 so then the critical value would be given by:

$F_{cric}= 7.779$

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

5 0

3 years ago

22: A 2.0 kg object moves along the x-axis under the influence of an unknown force. Its potential energy due to the force is U(x

aleksandr82 [10.1K]

Answer: a) -13.25 N, b) 1.78 m/sec

Step-by-step explanation:

Since we have given that

$U(x)=ax^4+bx^2$

where

$a=2.5\ J/m^4\\\\b=12\ J/m^2$

As we know that

$F=\dfrac{-dU}{dx}=-(4ax^3+2bx)$

Here, x= 0.5 m

So, it becomes,

$F=-(4\times 2.5\times (0.5)^3+2\times 12\times 0.5)=-13.25\ N$

Now, we need to find the velocity when it crosses the origin,

$F=mg\\\\F=m\dfrac{dv}{dt}\\\\F=mv\dfrac{dv}{dx}\\\\-(4ax^3+2bx)dx=mvdv\\\\\int\limits^{0.5}_0 {-(4ax^3+2bx)} \, dx =\int\limits {mv} \, dv\\\\ \dfrac{-4ax^4}{4}+\dfrac{2bx^2}{2}|_0^{0.5}=\dfrac{mv^2}{2}\\\\ax^4+bx^2|_0^{0.5}=\dfrac{mv^2}{2}\\\\2.5(0.5)^4+12(0.5)^2=\dfrac{2v^2}{2}\\\\0.15625+3=v^2\\\\3.15625=v^2\\\\\sqrt{3.15625}=v\\\\v=1.78$

Hence, a) -13.25 N, b) 1.78 m/sec

7 0

4 years ago

performance task applying probability concepts i need the work shown w answers any help is appreciated :)

nydimaria [60]

Where is the question?

5 0

3 years ago

Examine the graph of the logarithmic function f(x).

Eduardwww [97]

Answer:

The function f(x) has a vertical asymptote at x = 3

Step-by-step explanation:

We can define an asymptote as an infinite aproximation to given value, such that the value is never actually reached.

For example, in the case of the natural logarithm, it is not defined for x = 0.

Then Ln(x) has an asymptote at x = 0 that tends to negative infinity, (but never reaches it, as again, Ln(x) is not defined for x = 0)

So a vertical asymptote will be a vertical tendency at a given x-value.

In the graph is quite easy to see it, it occurs at x = 3 (the graph goes down infinitely, never actually reaching the value x = 3)

Then:

The function f(x) has a vertical asymptote at x = 3

6 0

3 years ago