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OlgaM077 [116]
3 years ago
5

Find the distance between (-7,-2) and (11,3)

Mathematics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

The answer is

<h2>\sqrt{349}  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }   \\</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-7,-2) and (11,3)

The distance between the points is

<h3>d =  \sqrt{ ({ - 7 - 11})^{2} +  ({ - 2 - 3})^{2}  }  \\  =  \sqrt{ ({ - 18})^{2} +  ({ - 5})^{2}  }  \\  =  \sqrt{324 + 25}  \\</h3>

We have the final answer as

<h3>\sqrt{349}  \:  \: units</h3>

Hope this helps you

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Which of the following is the solution to the inequality below?
Crank

Answer:

The correct answer should be x > -2

Step-by-step explanation:

-3(x - 3) > 5 - 5x

-3 + 9 > 5 - 5x

-3x + 5x + 9 > 5

-3x + 5x > 5 - 9

2x > 5 - 9

2x > -4

x > -2

Hope this helped! :)

3 0
3 years ago
Jee has scored 885 points on his month tests so far this semester. To get an A for the semester, he must
Dima020 [189]

Answer:?

Step-by-step explanation:

4 0
3 years ago
Chapter 5 • Measures of Central Tendency | 171
Black_prince [1.1K]

Answer: Rs. 5,033.30

Step-by-step explanation:

Total employees = 15 + 32 + 65 + 79 + 90 + 57 + 36 + 14 = 388

Median position = 388/2 = 194

Median therefore lies in range where cumulative employees is 194:

= 15 + 32 + 65 + 79 = 191

Median therefore lies in range after 4,000 - 4,999 which is 5,000 - 5,999.

Median = Lower limit of median range + range of median range * (median position - cumulative frequency up to median range) / frequency of median range

= 5,000 + 999 * (388/2 - 191)/90

= 5,000 + 33.3

= Rs. 5,033.30

8 0
3 years ago
Which of the following indicates a line segment?
Kazeer [188]

Answer:

A line segment is a line that starts somewhere and then ends somewhere.

Step-by-step explanation:

7 0
4 years ago
here are 12 marbles in a bag, and the marbles are either yellow or green. Two marbles will be randomly picked from the bag, with
Dima020 [189]

Answer:

D) 7

Step-by-step explanation:

Let y = number of yellow marbles in the bag

For the first marble

P(yellow) = number of yellow marbles over total

                =y/12

For the second draw, there are y-1 yellow marbles in the bag, and only 11 marbles left since we keep the first marble

P(2nd marble yellow) = (y-1)/11

The probability that the first and second marble are yellow when we keep the first marble is

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y * (y-1)       5

---------- = ----------

121               33

We can use cross products to solve

33 y(y-1) = 660

Divide each side by 33

y(y-1) = 660/33

y(y-1) = 20

Distribute

y^2 -y =20

Subtract 20

y^2 -y -20 =0

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4 0
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