Answer:
Step-by-step explanation:
7.3×10^22 = 73,000,000,000,000,000,000,000
73,000,000,000,000,000,000,000 × 26,000,000 = 1,898,000,000,000,000,000,000,000,000,000 or 1.898 × 10^30
Increase
The researcher records the following estimates: 450, 426, 310, 500, and 220.
The mean of these estimates is derived below.
Mean = (450+426+310+500+220)/5
=1906/5=381.2
If the researcher removes the estimate of 220.
The mean of the other numbers will be:
Mean =(450+426+310+500)/4
=1686/4=421.5
By comparison of the two mean, we can see that the value of the mean will increase.
x=2
y=-x+4 y=3x
3x=x+4
2x=4
(I hope this is the answer)
36-k
0.9995
10% = 0.10
1 - 0.10 = 0.9
n = number of light bulbs = 7
we calculate this using binomial distribution.
p(x) = nCx × p^x(1-p)^n-x
our question says at most 4 is defective
= (7C0 × 0.1⁰ × 0.9⁷) + (7C1 × 0.1¹ × 0.9⁶) + (7C2 × 0.1² × 0.9⁵) + (7C3 × 0.1³ × 0.9⁴) + (7C4 × 0.1⁴ × 0.9³)
= 0.478 + 0.372 + 0.1239 + 0.023 + 0.0026
= 0.9995
we have 0.9995 probability that at most 4 light bulbs are defective.