Need help to find the potential energy
1 answer:
You might be interested in
Answer:
2.52 × 10⁻² cm
Explanation:
The distance of bright fringe from the center of the screen is given by the formula
Here, wavelength is λ, Distance of the screen from the slits is D, seperation between the
slits is d.
Separation between the slits, d = 0.15 mm
Distance of the screen from the slits = 1.40 m
We have a wavelength, λ1 = 540 nm
=
By substituting all these values in the above equation we get
y1 = mλD/d
We have a wavelength, λ2 = 450 nm
=
By substituting all these values in the above equation we get
According to the problem, these two distance are coincides with each other.
So,
by testing values, the above equation is satisfied only when, m = 5 and m' = 6
Then from the above we have
y1 = y2 = 0.0252 m
= 2.52 × 10⁻² cm
Hi there,
for this question we have:
Signal 2.0 MHz = Emitted so we can call it
and we need the Reflected =
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted).
we also know: ΔBeat frequency(max) = 560 Hz =
so we have:
- =
so frequency of Reflected is:
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz =
now you know that Lambda = v/f
so if we find the lambda with our Emitted then we can find v with the Reflected:
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m
=>
= (lambda)(
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s
so the is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day
for this question we have:
Signal 2.0 MHz = Emitted so we can call it
and we need the Reflected =
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted).
we also know: ΔBeat frequency(max) = 560 Hz =
so we have:
so frequency of Reflected is:
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz =
now you know that Lambda = v/f
so if we find the lambda with our Emitted then we can find v with the Reflected:
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m
=>
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s
so the
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day