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3 years ago

Electromagnetic waves with the highest energy have what?

2 answers:

7 0

The Electromagnetic spectrum lists the most powerful emr, gamma rays, to the least powerful emr, radio waves. In addition, the highest energy waves (gamma, x-ray) have the shortest wavelengths. The lowest energy waves, radio waves, have longest wavelengths.

bezimeni [28]3 years ago

4 0

Electromagnetic waves with the highest energy have Shortest wavelength

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Beryllium has a charge of +2, and bromine has a charge of –1. Which is the best name for the ionic bond that forms between them?

Feliz [49]

Answer:

Beryllium bromide

Explanation:

There exists 2 elements in the question

Beryllium Be with valence of +2, and it's a metal

Bromine Br with a valence of -1, and is a non - metal.

Both of them combine together forming an ionic bond:

Be + Br(2) -> BeBr(2)

In naming the compound, we would say that since the first is a metal, beryllium, and the second being a halogen, bromine. We name it by calling the first name together with the last name and changing the last name of the non metal from -ine to -ide.

So we have, Beryllium Bromide.

4 0

3 years ago

Some metal conductor has a resistance of 12 ohms. When plugged into a circuit, the amount of heat 144J is released in 12s. What

worty [1.4K]

Answer:

12V

Explanation:

Given parameters:

Resistance = 12ohms

Heat released = 144J

Time taken = 12s

Unknown:

Voltage at the ends of the conductors = ?

Solution:

To solve this problem, we must first determine the power expended by the circuit.

Power is the rate at which work is done;

P = $\frac{work done }{time}$

= $\frac{144}{12}$

= 12W

Electrical power is given as;

P = IV = $\frac{V^{2} }{R}$

Since V is the unknown, we solve for it;

12 = $\frac{V^{2} }{12}$

V = 12V

5 0

3 years ago

Two children of mass 20.0 kg and 30.0 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If t

s2008m [1.1K]

Answer:

The distance from the pivot point that the small child will sit in order to maintain the balance is 1.8 m

Explanation:

Given;

mass of the bigger child, M = 30 kg

mass of the smaller child, m = 20 kg

distance between the two children, d = 3 m

This information can be represented diagrammatically;

|<------------------------------------------------>|

----------------------------------------------------------------------------

↓ x Δ 3-x ↓

20kg 30kg

x is the distance from the pivot point that the small child will sit in order to maintain the balance

Take moment about the pivot;

Clockwise moment = anticlockwise moment

30(3-x) = 20x

90 -30x = 20x

90 = 20x + 30x

90 = 50x

x = 90 / 50

x = 1.8 m

Therefore, the distance from the pivot point that the small child will sit in order to maintain the balance is 1.8 m

7 0

3 years ago

In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac

Elan Coil [88]

Answer:

$a=0.284\ m/s^2$

Explanation:

Given that,

Initially, the spaceship was at rest, u = 0

Final velocity of the spaceship, v = 11 m/s

Distance accelerated by the spaceship, d = 213 m

We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

$v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2$

So, the acceleration experienced by the occupants of the spaceship is $0.284\ m/s^2$ .

5 0

3 years ago

A stereo speaker is placed between two observers who are 40 m apart, along the line connecting them. if one observer records an

Nadya [2.5K]

The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m

Explanation:

Let's solve this problem in parts

let's start by finding the intensity of the sound in each observer

observer A β = 59 db

β = $10 log\frac{I_a}{I_o}$

where I₀ = $1 \times 10^{-12}$ W / m²

$I_a = I_b \times 10 ^{ \frac{\beta}{10} }$

$I_a = 1\times 10 ^{-12} \times 10 ^{ \frac{59}{10} }$

$I_a$ = $2.51 \times 10 ^{-6}$ W / m²

Similarly for Observer b $I_b = 3.16 \times 10 ^ {-4}$

now we use that the emitted power that is constant is the intensity over the area of the sphere where the sound is distributed

P = I A

therefore for the two observers

the area of a sphere is

$A= 4\pi \times r^2$

we substitute the above formula, we get

Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute

$I_a (35 -x) ^2 = I_b x^2$

after solving the above equation we get x = 28.64 m

This is the distance of observer A

similarly The distance from observer B is 35 - x

= 40 - 28.64

= 11.36m

To know more about intensity of sound with the given link

#SPJ4

6 0

1 year ago