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lawyer [7]
3 years ago
12

Which measure of central tendency refers to the value that appears most frequently in a data set?

Physics
2 answers:
Sloan [31]3 years ago
5 0

The other answer is correct, but doesn't give the answer needed, so continuing with that:

Median- Separates data sample, "middle" value.

Mode- The value that appears most often.

Mode is a measure of central tendency that refers to the value that appears most frequently in a data set.

For anyone still looking for the answer = )

<em>(This answer was copied/pasted from another question, which I also answered.)</em>

Bezzdna [24]3 years ago
3 0

Median and Mode;

The only measures of central tendency that can be used for ordinal data.

<u>Values are ranked relative to each other but are not measured absolutely.</u>

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w=10,000,000 Joules

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X_{t`2} = v_i \sqrt{\frac{2X}{a} } + 0.5 a\sqrt{\frac{2X}{a} }\\X_{t`2} =  (v_i + 0.5 a) \sqrt{\frac{2X}{a} }\\X_{t`2} =  ( 19 + 2)  \sqrt{\frac{2* 52}{4} }\\X_{t`2} =  21 * 5.09\\X_{t`2} = 107.07

4 0
3 years ago
A mass of 150 g stretches a spring 1.568 cm. If the mass is set in motion from its equilibrium position with a downward velocity
nadezda [96]

Answer:

u(t)=\frac{1}{5} sin\ (25t)

Explanation:

Given:

  • mass of the body stretching the spring, m=150\ g
  • extension in spring, \Delta x=1.568\ cm
  • velocity of oscillation, u'(0)=20\ cm.s^{-1}
  • initial displacement position of equilibrium, u(0)=0

<u>According to given:</u>

m.g=k.\Delta x

150\times 980=k\times 1.568

k=93750\ dyne.cm^{-1}

<u>we know frequency:</u>

\omega=\sqrt{\frac{k}{m} }

\omega=\sqrt{\frac{93750}{150} }

\omega=25

Now, for position of mass in oscillation:

u= A.sin\ (\omega.t)+B.cos\ (\omega.t)

u= A.sin\ (25.t)+B.cos\ (25.t)

at t=0;\ u(0)=0\ \Rightarrow A=0

∴u(t)=B.sin\ (25.t)

∵ at t=0;\ u'(0)=20\ cm.s^{-1}\ \Rightarrow B=\frac{1}{5}

u(t)=\frac{1}{5} sin\ (25t)

7 0
3 years ago
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