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Zielflug [23.3K]
3 years ago
8

If the mass of the object is doubled and the speed is halved then kinetic energy will change by a factor of:

Physics
1 answer:
madam [21]3 years ago
3 0

Answer:

kinetic energy will change by a factor of 1/2

Option C) 1/2 is the correct answer

Explanation:

Given the data in the question;

we know that;

Kinetic energy = 1/2.mv²

given that mass of the object is doubled; m1 = 2m

speed is halved; v1 = V/2

Now, New kinetic energy will be; 1/2.m1v1²

we substitute

Kinetic Energy = 1/2 × 2m × (v/2)²

Kinetic Energy = 1/2 × 2m × (v²/4)

Kinetic Energy = 1/2 × m × (v²/2)

Kinetic Energy = 1/2 [ 1/2mv² ]

Kinetic Energy = 1/2 [ KE ]

Therefore; kinetic energy will change by a factor of 1/2

Option C) 1/2 is the correct answer

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Does coefficient of linear expansion depends on length​
nlexa [21]

Answer:

yes

Explanation:

As the formula is α= ΔL/L*ΔT  where alpha (α) is the sign of coefficient of linear expansion

5 0
3 years ago
A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with
Ymorist [56]

Answer:

the frequency of the beats is 8.7687 kHz

Explanation:  

Given the data in the question;

The frequency for stationary source and moving observer is;

f' = f( 1 +( v_observer/v_sound))

we know that, speed of sound in dry air =  343 m/s

so we substitute

f' = 41.2 kHz( 1 + (33.0 m/s / 343 m/s) ) = 41.2kHz( 1 + 0.0962) = 41.2kHz(1.0962)

f' = 45.1634 kHz

Now the frequency for stationary observer and moving source with frequency f' will be

f" = f'( 1 / (1 - ( v_observer/v_sound)))

45.1634 kHz( 343 / 343 - 33)

we substitute

f" = 45.1634 kHz( 1 / (1 - (33.0 m/s / 343 m/s)))

f" = 45.1634 kHz( 1 / (1 - 0.0962))

f" = 45.1634 kHz( 1 / 0.9038 )

f" = 45.1634 kHz( 1.1064 )

f" = 49.9687 kHz

Now the beat frequency will be;

f_beat = f' - f

we substitute

f_beat = 49.9687 kHz - 41.2 kHz

f_beat = 8.7687 kHz

Therefore, the frequency of the beats is 8.7687 kHz

7 0
3 years ago
What is the main function of chloroplasts?
dangina [55]

Answer:

C

To convert sunlight into usable sugars

(

Explanation:

6 0
4 years ago
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jonny [76]

Answer:

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7 0
3 years ago
At one instant a bicyclist is 21.0 m due east of a park's flagpole, going due south with a speed of 13.0 m/s. Then 21.0 s later,
andre [41]

Answer:

Part a)

d = 21\sqrt2 = 29.7 m

Part b)

Direction is 45 degree North of West

Part c)

v_{avg} = 1.41 m/s

Part d)

direction of velocity will be 45 Degree North of West

Part e)

a = 0.875 m/s^2

Part f)

\theta = 45 degree North of East

Explanation:

Initial position of the cyclist is given as

r_1 = 21.0 m due East

final position of the cyclist after t = 21.0 s

r_2 = 21.0 m due North

Part a)

for displacement we can find the change in the position of the cyclist

so we have

d = r_2 - r_1

d = 21\hat j - 21\hat i

so magnitude of the displacement is given as

d = 21\sqrt2 = 29.7 m

Part b)

direction of the displacement is given as

\theta = tan^{-1}\frac{y}{x}

\theta = tan^{-1}\frac{21}{-21}

so it is 45 degree North of West

Part c)

For average velocity we know that it is defined as the ratio of displacement and time

so here the magnitude of average velocity is defined as

v_{avg} = \frac{\Delta x}{t}

v_{avg} = \frac{29.7}{21}

v_{avg} = 1.41 m/s

Part d)

As we know that average velocity direction is always same as that of average displacement direction

so here direction of displacement will be 45 Degree North of West

Part e)

Here we also know that initial velocity of the cyclist is 13 m/s due South while after t = 21 s its velocity is 13 m/s due East

So we have

change in velocity of the cyclist is given as

\Delta v = v_f - v_i

\Delta v = 13\hat i - (-13\hat j)

now average acceleration is given as

a = \frac{\Delta v}{\Delta t}

a = \frac{13\hat i + 13\hat j}{21}

so the magnitude of acceleration is given as

a = \frac{13\sqrt2}{21} = 0.875 m/s^2

Part f)

direction of acceleration is given as

\theta = tan^{-1}\frac{y}{x}

\theta = tan^{-1}\frac{13}{13}

\theta = 45 degree North of East

4 0
3 years ago
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