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tatyana61 [14]
3 years ago
6

Identify the breed of goat in the picture.

Physics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

Nubian goat

Explanation:

Hope this helps and have a great day!!!

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A brick sits on the top of a hill with a gravitational potential energy of 245 J. To determine the gravitational potential of th
Bogdan [553]

Answer:

The mass of the object, its acceleration due to gravity and the distance between the top of the hill and the ground level.

Explanation:

gravitational potential energy is the energy possessed by a body under influence of gravitational force by virtue of its position.

In order to determine the gravitational potential energy of the brick, we must know the mass (m) of the brick, its acceleration due to gravity (g) since it is acting under the influence of gravitational force and the distance between the top of the hill and the ground level. (The height).

Potential energy of a body is calculated as mass × acceleration due to gravity × height.

5 0
3 years ago
What is the name of the process the puts adenosine diphosphate (ADP) and phosphate (P) together to reform ATP?
hoa [83]
I think the correct answer is hydrolysis. The name <span>of the process that puts adenosine diphosphate (ADP) and phosphate (P) together to reform ATP is called hydrolysis. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
6 0
3 years ago
Figure 2. sketch of bar and magnetic field lines observations PLEASE HELPPPP ​
labwork [276]
Hope this sketch helps

5 0
3 years ago
What is the de broglie wavelength of a 149-g baseball traveling at 95.4 mph? (1 mile = 1.609 km, h = 6.63 × 10–34 j·s)?
boyakko [2]

The solution for the problem is:

Wavelength = Planck’s constant/(mass*velocity) 

Planck’s constant= 6.63*10^-34 with units of J-s or kg-m^2/s^2-s 

mass = 149g = 0.149 kg 

velocity = 95.4.mi/1hr(1609.3m/1mi)(1hr/3600sec) = 42.65m/s 

h/mv = 6.63*10^-34 kg-m^2/s^2-s/(42.65m/s*0.149kg)

wavelength = 1.04 *10^-34 m

5 0
3 years ago
10. A satellites is in a circular orbit around the earth at a height of 360 km above the earth’s surface. What is its time perio
Afina-wow [57]

Answer:

Orbital speed=8102.39m/s

Time period=2935.98seconds

Explanation:

For the satellite to be in a stable orbit at a height, h, its centripetal acceleration V2R+h must equal the acceleration due to gravity at that distance from the center of the earth g(R2(R+h)2)

V2R+h=g(R2(R+h)2)

V=√g(R2R+h)

V= sqrt(9.8 × (6371000)^2/(6371000+360000)

V= sqrt(9.8× (4.059×10^13/6731000)

V=sqrt(65648789.18)

V= 8102.39m/s

Time period ,T= sqrt(4× pi×R^3)/(G× Mcentral)

T= sqrt(4×3.142×(6.47×10^6)^3/(6.673×10^-11)×(5.98×10^24)

T=sqrt(3.40×10^21)/ (3.99×10^14)

T= sqrt(0.862×10^7)

T= 2935.98seconds

4 0
3 years ago
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