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leonid [27]
3 years ago
7

Solve the system of linear equations by graphing. y=x+1 y=3x-1

Mathematics
1 answer:
Arada [10]3 years ago
3 0

If you find a problem on answer respond me

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What is the sum of 7 of the interior angles of a regular decagon?
Setler [38]

Answer:1440 degrees

Step-by-step explanation:

The interior angles of a decagon is 1440 degrees. All sides are the same length (congruent) and all interior angles are the same size.

5 0
3 years ago
How much is 85cm longer than 1m ?
balandron [24]

1 meter has 100 CENTImeters.

now, 85cm is not longer than 1 meter clearly, because 100 cm > 85 cm.

so one can say, that is 1 meter is longer by 15cm instead.

100 -  85 = 15.

7 0
3 years ago
Read 2 more answers
A rectangular cracker has a length of 5 centimeters and an area f 20 square centimeters. Find its perimeter.
iren [92.7K]

Answer:

18cm

Step-by-step explanation:

We have the length of the rectangle but we need to find the width which we'll call w. Area is a, l is length.

a = l * w

20 = 5 * w

divide both sides by 5 to cancel the multiplication by 5 on the right side

4 = w

The rectangle is going to have two sides that are the length of l, and two sides that are the the length of w. We're looking for the perimiter p.

p = 2l + 2w

p = (2 * 5) + (2 * 4)

p = 18

4 0
2 years ago
Find the slope of the line containing the points (7,5) and (9,5).
svet-max [94.6K]

Answer:

\frac{2}{4}

Step-by-step explanation:

Remember that in order to find the slope of two points you need to substitute the variables and subtract making sure you keep the 2's and the 1's together.

m=\frac{y2-y1}{x2-x1}

Plugin your numbers:

=\frac{7-5}{9-5}

7-5=2

9-5=4

=\frac{2}{4}

Hope this helps.

5 0
3 years ago
Read 2 more answers
Solve the equation (linear equation)<br><br> <img src="https://tex.z-dn.net/?f=8%5E%7B2x%2B7%7D%20%3D%20%28%5Cfrac%7B1%7D%7B32%7
Minchanka [31]

Answer: x=-1

Step-by-step explanation:

By the negative exponent rule, you have that:

(\frac{1}{a})^n=a^{-n}

By the exponents properties, you know that:

(m^n)^l=m^{(nl)}

Therefore, you can rewrite the left side of the equation has following:

(\frac{1}{8})^{-(2x+7)}=(\frac{1}{32})^{3x}

 Descompose 32 and 8 into its prime factors:

32=2*2*2*2*2=2^5\\8=2*2*2=2^3

Rewrite:

(\frac{1}{2^3})^{-(2x+7)}=(\frac{1}{2^5})^{3x}

Then:

(\frac{1}{2})^{-3(2x+7)}=(\frac{1}{2})^{5(3x)}

As the base are equal, then:

-3(2x+7)=5(3x)

Solve for x:

-6x-21=15x\\-21=15x+6x\\-21=21x\\x=-1

8 0
3 years ago
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