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scZoUnD [109]
2 years ago
11

How do you find the pH of the compound KCl?

Chemistry
1 answer:
Sergeu [11.5K]2 years ago
7 0
Google it - that’s how
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Rank the following in terms of increasing ionization energy: Sulfur, oxygen, hydrogen, and fluorine.
Naily [24]

Answer:

Ranked from lowest to highest:

Sulfur - 999.6 kJ/mol

Hydrogen - 13.5984 kJ/mol

Oxygen - 13.6181 kJ/mol

Fluorine - 17.4228 kJ/mol

3 0
2 years ago
What is the difference between electron behavior in ionic and covalent bonds?
Flauer [41]

a electron behavior is a subatomic particle whose electric i charge and the other one is a molecule and chemical bond that shares electrons

8 0
3 years ago
A substance has a volume of 50L and a density of 10.36g/l. What is the mass of the substance?
Lelechka [254]

Answer:

518 g

Explanation:

50L x 10.36 g/L = 518g

3 0
2 years ago
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Calculate the DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide. DH°f means delta or change
USPshnik [31]

Answer: +178.3 kJ

Explanation:

The chemical equation  follows:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(CaO(s))})+(1\times \Delta H^0f_{CO_2}]-[(1\times \Delta H^o_f_{(CaCO_3(s))})]

We are given:

\Delta H^o_f_{(CaO(s))}=-635.1kJ/mol\\\Delta H^o_f_{(CaCO_3(s))}=-1206.9kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-635.1))+(1\times (-393.5))]-[(1\times (-1206.9))]

The DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide is +178.3 kJ

5 0
3 years ago
In science, Bob learns that the energy of a wave is directly proportional to the square of the waves amplitude. If the energy of
Illusion [34]
Jamuuj ExpertThe energy of a wave is directly proportional to the square of the waves amplitude. Therefore, E = A² where A is the amplitude. This therefore means when the amplitude of a wave is doubled the energy will be quadrupled, when the amplitude is tripled the energy increases by a nine fold and so on.Thus, in this case if the energy is 4J, then the amplitude will be  √4 = 2 .
4 0
3 years ago
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