Answer:
E. 1.5M
Explanation:
because there is total 175.32 g of NaCl dissolved in 2 liter of water, and 58.44 g = 1 mol
so total miles = 175.32/58.32 = 3 moles
now 3 moles are in 2 liter of water, hence one liter contains 3/2= 1.5
Therefore answer is E. 1.5M
<span>It contains 6.02mc001-2 particles of a given substance</span>
Answer:
d. Copper (II) sulfate
Explanation:
Given data:
Mass of Al = 1.25 g
Mass of CuSO₄ = 3.28 g
What is limiting reactant = ?
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂ (SO₄)₃ + 3Cu
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 1.25 g/ 27 g/mol
Number of moles = 0.05 mol
Number of moles of CuSO₄:
Number of moles = mass/molar mass
Number of moles = 3.28 g/ 159.6 g/mol
Number of moles = 0.02 mol
now we will compare the moles of reactant with product.
Al : Al₂ (SO₄)₃
2 : 1
0.05 : 1/2×0.05=0.025 mol
Al : Cu
2 : 3
0.05 : 3/2×0.05 = 0.075 mol
CuSO₄ : Al₂ (SO₄)₃
3 : 1
0.02 : 1/3×0.02=0.007 mol
CuSO₄ : Cu
3 : 3
0.02 : 0.02
Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.
The thermal energy needed to completely melt 9.60 mole of ice at 0.0 C is 57.8 Kj
Explanation
ice melt to form water
The molar heat of fusion for water is 6.02 Kj/mol
Thermal energy = moles x molar heat of fussion for water
=9.6 mol x6.02 kj/mol =57.8 Kj
Answer:
An excellent experiment is to heat sodium thiosulfate in a water bath. The solid crystals will dissolve into the water in the hydrated crystals forming a supersaturated solution. ... Placing a small crystal in the supersaturated solution will cause the liquid to turn solid.
