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3 years ago

Write the complete thermochemical equation (including energy) for the combustion of hexane.

1 answer:

5 0

2C₆H₁₄+19O₂⇒14H₂O+12CO₂+energy
You can tell that the energy is on the left side since the reactoin is highly exothermic meaning it releases heat which can also be thought of as energy.

I hope this helps

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A gas that exerts a pressure of ? bar in a container with a volume of 0.5650 L will exert a pressure of 715.1 bar when transferr

uranmaximum [27]

Robert Boyle, the 17th century British chemist, first noticed that the volume of a given amount of gas is inversely proportional to its pressure when kept at a constant temperature. When working with ideal gases we use PV = nRT, but remember n, R, and T are all constant. Therefore we have:

PV(before) = PV(after)

P(0.5650) = (715.1)(1.204)

8 0

3 years ago

Read 2 more answers

When 70.4 g of benzamide (C7H7NO) are dissolved in 850. g of a certain mystery liquid X, the freezing point of the solution is 2

Arlecino [84]

Answer:

1.62

Explanation:

From the given information:

number of moles of benzamide $=\dfrac{70.4 \ g}{121.14 \ g/mol}$

= 0.58 mole

The molality = $\dfrac{mass \ of \ solute (i.e. \ benzamide )}{mass \ of \ solvent }$

$= \dfrac{0.58 }{0.85 }$

= 0.6837

Using the formula:

$\mathbf {dT = l \times k_f \times m}$

where;

dT = freezing point = 27

l = Van't Hoff factor = 1

kf = freezing constant of the solvent

∴

2.7 °C = 1 × kf × 0.6837 m

kf = 2.7 °C/ 0.6837m

kf = 3.949 °C/m

number of moles of NH4Cl = $\dfrac{70.4 \ g}{53.491 \ g /mol}$

= 1.316 mol

The molality = $\dfrac{1.316 \ mol}{0.85 \ kg}$

= 1.5484

Thus;

the above kf value is used in determining the Van't Hoff factor for NH4Cl

i.e.

9.9 = l × 3.949 × 1.5484 m

$l = \dfrac{9.9}{3.949 \times 1.5484 \ m}$

l = 1.62

5 0

3 years ago

A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t

777dan777 [17]

The molar extinction coefficient is 15,200 $M^{-1} cm^{-1}$ .

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = $\frac{A}{cl}$

ξ = $\frac{1.140}{1.5*10^{-4}*0.5 }$

Performing multiplication in denominator to find the value of molar extinction coefficient

ξ = $\frac{1.140}{0.000075}$

Performing division to find the value of molar extinction coefficient

ξ = 15,200 $M^{-1} cm^{-1}$

Hence, the molar extinction coefficient is 15,200 $M^{-1} cm^{-1}$ .

Learn more about molar extinction coefficient -

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6 0

2 years ago

Using the perodic table determine the number of protons for the element Li

wolverine [178]

Answer is 3

because on the periodic table, the small number above every element is the number of protons

8 0

3 years ago

ANYONE THATS GOOD WITH CHEMISTRY PLEASE HELP!

sergejj [24]

CH2O. You can reduce 8, 16, and 8 to 1, 2, and 1. You just simplify the numbers. When there is no number after an element, it means that there is one of them.

5 0

3 years ago