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shtirl [24]
3 years ago
10

Classify each of these reactions. Ba(ClO3)2 → BaCl2 3 O2 double replacement combination single replacement decomposition CaO CO2

→ CaCO3 double replacement single replacement combination decomposition NaNO2 2 HCl → NaCl HNO2 single replacement combination double replacement decomposition Mg ZnSO4 → MgSO4 Zn single replacement combination double replacement decomposition
Chemistry
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

Ba(ClO₃)₂ → BaCl₂ +  3 O₂ <em>Descomposition. </em>

CaO + CO₂ → CaCO₃ <em>Combination. </em>

NaNO₂ +  HCl → NaCl + HNO₂ <em>Double replacement. </em>

Mg + ZnSO₄ → MgSO₄ + Zn <em>Single replacement. </em>

Explanation:

A combination reaction is defined as a reaction in which two or more substances combine to form a single new substance.

A + B → AB

A descomposition reaction is defined as a reaction in which a compound breaks down into two or more simpler substances.

AB → A + B

A double replacement is a chemical reaction were the positive and negative ions of two ionic compounds exchange places to form two new compounds.

AB + CD → AD + CB

A single replacement is another type of reaction were one element replaces a similar element in a compound.

A + BC → AC + B

Thus, with this information it is possible to classify these reactions as:

Ba(ClO₃)₂ → BaCl₂ +  3 O₂ <em>Descomposition. </em>One single molecule breaks down into two or more molecules

CaO + CO₂ → CaCO₃ <em>Combination. </em>Two substances are combined to form one single molecule

NaNO₂ +  HCl → NaCl + HNO₂ <em>Double replacement. </em>Na and H are exchange places to form two new compounds

Mg + ZnSO₄ → MgSO₄ + Zn <em>Single replacement. </em>Mg is replacing Zn.

I hope it helps!

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What is the minimum of acetic anhydride (102.1 g/mol) required to react completely with the 2.94 grams of salicylic acid? What v
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Answer:

a) the minimun of acetic anhydride required for the  reaction is 2.175 g (CH3CO)2O

b) V acetic anhydride = 2.010 mL

Explanation:

  • balanced reaction:

      C6H4OHCOOH + (CH3CO)2O  ↔  C9H8O4 + C2H4O2

⇒ mol salicylic acid = 2.94 g C6H4OHCOOH * ( mol C6H4OHCOOH / 138.121 g ) = 0.0213 mol C6H4OHCOOH

⇒ mol acetic anhydride = 0.0213 mol C6H4OHCOOH * ( mol (CH3CO)2O /  mol  C6H4OHCOOH ) = 0.0213 mol (CHECO)2O

⇒ g acetic anhydride = 0.0213 mol * ( 102.1 g/mol ) = 2.175 g CH3CO)2O

b) V = 2.175 g (CH3CO)2 * ( mL / 1.082 g ) = 2.010 mL (CH3CO)2O

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