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shtirl [24]
3 years ago
10

Classify each of these reactions. Ba(ClO3)2 → BaCl2 3 O2 double replacement combination single replacement decomposition CaO CO2

→ CaCO3 double replacement single replacement combination decomposition NaNO2 2 HCl → NaCl HNO2 single replacement combination double replacement decomposition Mg ZnSO4 → MgSO4 Zn single replacement combination double replacement decomposition
Chemistry
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

Ba(ClO₃)₂ → BaCl₂ +  3 O₂ <em>Descomposition. </em>

CaO + CO₂ → CaCO₃ <em>Combination. </em>

NaNO₂ +  HCl → NaCl + HNO₂ <em>Double replacement. </em>

Mg + ZnSO₄ → MgSO₄ + Zn <em>Single replacement. </em>

Explanation:

A combination reaction is defined as a reaction in which two or more substances combine to form a single new substance.

A + B → AB

A descomposition reaction is defined as a reaction in which a compound breaks down into two or more simpler substances.

AB → A + B

A double replacement is a chemical reaction were the positive and negative ions of two ionic compounds exchange places to form two new compounds.

AB + CD → AD + CB

A single replacement is another type of reaction were one element replaces a similar element in a compound.

A + BC → AC + B

Thus, with this information it is possible to classify these reactions as:

Ba(ClO₃)₂ → BaCl₂ +  3 O₂ <em>Descomposition. </em>One single molecule breaks down into two or more molecules

CaO + CO₂ → CaCO₃ <em>Combination. </em>Two substances are combined to form one single molecule

NaNO₂ +  HCl → NaCl + HNO₂ <em>Double replacement. </em>Na and H are exchange places to form two new compounds

Mg + ZnSO₄ → MgSO₄ + Zn <em>Single replacement. </em>Mg is replacing Zn.

I hope it helps!

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The attraction which exists between carbon diozide molecules in solid carbon dioxide is due to
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Answer:

Van der waal's  force of attraction

Explanation:

Van der waal's  force of attraction

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3 years ago
A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th
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Explanation:

The given data is as follows.

Solvent 1 = benzene,          Solvent 2 = water

 K_{p} = 2.7,         V_{S_{2}} = 100 mL

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       Extract = 3

Therefore, calculate the fraction remaining as follows.

                  f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}

                                  = [1 + 2.7(\frac{100}{10})]^{-3}

                                  = (28)^{-3}

                                  = 4.55 \times 10^{-5}

Hence, weight of compound to be extracted = weight of compound - fraction remaining

                                  = 1 - 4.55 \times 10^{-5}

                                  = 0.00001

or,                               = 1 \times 10^{-5}

Thus, we can conclude that weight of compound that could be extracted is 1 \times 10^{-5}.

7 0
3 years ago
Read 2 more answers
The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) â 4 no2 (g) + 6 h2o (g) the
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The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2 
so 1mole of NH3 will give 1 mole of NO2 
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3 years ago
When the pressure on 2.5 liters of oxygen is decreased from 2.0 atm to 1.0 atm, the volume of the gas
uranmaximum [27]

Answer:

volume of the gas is 5.0L

Explanation:

Using Boyle's law that state the pressure of a gas is inversely proportional to volume of it occupies when temperature is constant, it is possible to write:

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<em>Where P is pressure, V is volume and 1 and 2 are initial and final states.</em>

<em />

If initial volume is 2.5L, initial pressure is 2.0atm and 1.0atm is final pressure, final volume is:

2.0atm*2.5L = 1atm V₂

5.0L = V₂

Thus, <em>volume of the gas is 5.0L</em>.

5 0
3 years ago
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