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ANEK [815]
3 years ago
6

If δh = -70.0 kj and δs = -0.500 kj/k , the reaction is spontaneous below a certain temperature. calculate that temperature. exp

ress your answer numerically in kelvins.
Chemistry
1 answer:
Nina [5.8K]3 years ago
6 0
Answer is: temperature must be less than 140 K.
Gibbs free energy (G) determines if reaction will proceed spontaneously. <span>If the value of G is a negative, the reaction is spontaneous. <span>ΔG = ΔH - T·ΔS.
</span></span>ΔH = -70.00 kJ.
ΔS = -0.500 kJ/K.
-70 kJ = T · (-0.5 kJ/K).
T = -70.00 kJ ÷ (-0.500 kJ/K).
T = 140 K. 
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