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Charra [1.4K]
3 years ago
5

A gas mixture with a total pressure of 765 mmHg contains each of the following gases at the indicated partial pressures: 134 mmH

g CO2, 214 mmHg Ar, and 190 mmHg O2. The mixture also contains helium gas. Part A What is the partial pressure of the helium gas? Express your answer in millimeters of mercury.
Chemistry
1 answer:
ladessa [460]3 years ago
4 0

Answer: c

Explanation:

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Examples of conduction
Sonja [21]

Answer:

Conduction: Touching a stove and being burned. Ice cooling down your hand. Boiling water by thrusting a red-hot piece of iron into it.

Explanation:

3 0
3 years ago
Which of the following environments are low-level areas that can be temporarily or seasonally filled with water?
Oliga [24]

Answer:

Rainforest

Explanation:

Swamps are permanently filled with water

and Tundras are dry and cold so the answer should be Rainforest

4 0
3 years ago
The rate constant for this second‑order reaction is 0.380 M − 1 ⋅ s − 1 0.380 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
Sati [7]

Answer: 8.38 seconds

Explanation:

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

a_0 = initial concentartion = 0.860 M

a= concentration left after time t = 0.230 M

k = rate constant =0.380M^{-1}s^{-1}

\frac{1}{0.860}=0.380\times t+\frac{1}{0.230 }

t=8.38s

Thus it will take 8.38 seconds for the concentration of  A to decrease from 0.860 M to 0.230 M .

5 0
3 years ago
C2H6 (g) + O2 (g) → CO2 (g) + H2O (g) (not balanced) Determine the number of liters of CO2 formed at STP when 240.0 grams of C2H
Dmitry_Shevchenko [17]

Answer:

13.44dm^3

Explanation:

To calculate this we first need to know the number of mole produced. We will first need to balance the equation to know the theoretical mole ratio.

C2H6 (g) + 3.5O2 (g) → 2CO2 (g) + 3H2O (g)

From the balanced equation, we can deduce that one mole of ethane yielded 2 moles of carbon iv oxide. We use this information to calculate the actual number of moles yielded.

24g were reacted. Now to know the number of moles reacted, we simply divide the mass by the molar mass. The molar mass of ethane is 2(12) +6(1)= 40g/mol

The number of moles is thus 24/40 = 0.6 moles

Like we said earlier, one mole yielded 2 moles of carbon iv oxide, hence, 0.6 moles will yield 0.6 * 2 = 0.12 moles of carbon iv oxide.

Now, at stp, one mole of a gas occupies a volume of 22.4dm^3 thus, 0.6 mole will occupy 0.6 * 22.4 = 13.44dm^3

8 0
3 years ago
If a large chunk of sulfur is ground into powder, its mass will ___
pochemuha
Its mass will stay the same
8 0
3 years ago
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