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2 years ago

How would the melting point of an ice cube compare to the melting point of a large ice sculpture?

Chemistry

2 answers:

Ad libitum [116K]2 years ago

7 0

The ice sculpture would take longer to melt than the ice cube

aksik [14]2 years ago

3 0

Because the ice sculpture is larger it takes more energy to melt, so it will take longer to melt, but the melting point is still the same because both of the solids are made of water. hope that made sense :)

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Calculate the molar mass of ammonium chloride

il63 [147K]

Answer:

53.491 g/mol

Explanation:

Create the chemical compound and find each individual element's molar mass. Lastly, add them up.

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2 years ago

How many grams are in 5.60 moles of sodium hydroxide (NaOH)

Illusion [34]

Answer: I believe it should be 224g.

Explanation: There are 40g for every one mole of NaOH, so multiply the two to get to 224. I hope that helps!

8 0

2 years ago

Read 2 more answers

Be able to identify the correct elements using clues such as numbers of protons,locations (family/period), number of neutrons, n

Brilliant_brown [7]

an element's name, chemical symbol, atomic number, atomic mass.

IDK what you are even asking for

6 0

3 years ago

Protons, neutrons, and electrons.

natima [27]

What are you asking?

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3 years ago

Determine the molarity of a 6.0 mole% sulfuric acid solution with SG-a 1.07 Note: Atomic Weight: S (32), O 16); H (O)

marin [14]

Answer:

The molarity of a 6.0 mole% sulfuric acid solution is 2.8157 Molar.

Explanation:

Suppose there are 100 moles in solution:

Moles of sulfuric acid = 6% of 100 moles = 6 moles

Mass of 6 moles of sulfuric acid = 6 mol × 98 g/mol=588 g

Moles of water = 100%- 6% = 94%= 94 moles

Mass of water = 94 mol × 18 g/mol = 1692 g

Specific gravity of the solution ,S.G= 1.07

Density of solution = D

$S.G=\frac{D}{d_w}$

$d_w$ = density of water = 1 g/mL

$D=S.G\times d_w=1.07\times 1 g/mL=1.07 g/mL$

Mass of the solution = 588 g + 1692 g = 2280 g

Volume of the solution = V

Volume = $\frac{Mass}{Density}$

$=\frac{2280 g}{1.07 g/mL}=2130.84 mL=2.13084 L$

1 mL = 0.001 L

$Molarity = \frac{n}{V(L)}$

n = number of moles of compound

V = volume of the solution in L

here we have ,n = 6 moles of sulfuric acid

V = 2.13084 L

So, the molarity of the solution is :

$Molarity=\frac{6 mol}{2.13084 L}=2.8157 mol/L$

5 0

2 years ago