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Kamila [148]
3 years ago
10

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

formula d = –16t2 + 1,000. Use an inequatily equation to find for the interval of time taken by the object to reach the height greater than 300 feet above the ground
Mathematics
2 answers:
dusya [7]3 years ago
6 0
-16t^2 + 1000 > 300
16t^2 < 1000 - 300
16t^2 < 700
t^2 < 700/16
t^2 < 43.75
t < 6.61
IRINA_888 [86]3 years ago
5 0
Find where it equals 300
300=-16t²+1000
minus 1000 from both sides
-700=-16t²
divide both sides by -16
43.75=t²
square root both sides
6.614=t

it took at 6.614 seconds to get to  a height of 300 ft above the ground
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Examine the system of equations.
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<h3><u>Explanation</u></h3>
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