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aliya0001 [1]
3 years ago
11

Find the reference angle for 404 degrees

Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0
It would have to be 44°. If you go around 360° nothing happens. So subtract 404°-360° and you get 44°. 44°<90° from the x-axis so we are done.
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Breanna thought of a number, added 6 to it, multiplied it by 6, subtracted 6 from her answer, and then divided it by 6. She got
ss7ja [257]

Answer:5

Step-by-step explanation:

If you look at the question in reverse you can backtrack your way through. Take 10 and instead of dividing, multiply it by 10, which is 60, add 6 instead of subtracting, which is 66, divide by 6 instead of multiplying, which is 11 and finally subtract 6 instead of adding, which is 5. Use five and try the question over to make sure you calculated correct.

8 0
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In ΔABC, the measure of ∠C=90°, the measure of ∠B=64°, and BC= 6.6 Find the length of CA the nearest tenth of a foot
Marrrta [24]

Answer:

CA = 13.5

Step-by-step explanation:

tan 64 = CA/6.6

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3 years ago
Lynn plotted point G, 3 units to the left and 2 units above point F. Where did lynn plot point G?
kvasek [131]

Answer:

G = (2,6)

Step-by-step explanation:

See Attachment for Complete Question

From the attachment, we can see that F is plotted at

F = (5,4)

On the x axis, G is 3 units to the left;

And on the y axis, G is 2 units above

So, the coordinates of G is calculated as:

G = (5-3,4+2)

G = (2,6)

Hence:

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4 0
3 years ago
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Gnesinka [82]

p(x)= x-2

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first we have to find the zero of the polynomial of x-2

p(x)= x-2 = 0

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therefore,

p(x)= 2x^3 + 3x^2 - 11x - 6

p(2)= 2*2^3 + 3*2^2 - 11*2 - 6

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      = 16 + 12 - 22 - 6

      = 28-28

     = 0

Hope it helped u, ^_^.

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