Answer:
<h3>20.5 IS YOUR ANSWER,,,,,,,,,,,,,,,</h3>
This is an incomplete question, here is a complete question.
What is a peregrine falcon's maximum speed while diving to catch prey 200 miles per hour in feet per second? (Round your answer to the nearest whole number. (1 mile = 5280 feet)
Answer : The speed in feet per second is, 293 feet/s
Step-by-step explanation :
As we are given that the speed of peregrine falcon's is 200 miles per hour. Now we have to determine the speed in feet per second.
As we know that:
1 mile = 5280 feet
1 hour = 3600 second
So,
1 mile/hr = 1.4667 feet/s
As, 1 mile/hr = 1.4667 feet/s
So, 200 mile/hr = 
= 293.34 feet/s ≈ 293 feet/s
Therefore, the speed in feet per second is, 293 feet/s
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Answer:
9:100
Step-by-step explanation:
Turn 9% into a fraction by putting it over a hundred:
9/100
Then simply change the '/' into ':'
If this were another fraction, let's say, 4/6, then you'd put it in simplest form, which is 2/3 = 2:3
Answer:
- time: t = -0.3
- minimum: v = 0.55
Step-by-step explanation:
For quadratic ax^2 + bx + c, the extreme value is found at x=-b/(2a). For your quadratic, the minimum is found at ...
t = -(3)/(2(5))
t = -0.3 . . . . . time of minimum velocity
__
The value of velocity at that time is ...
v = 5(-0.3)^2 +3(-0.3) +1 = 5(.09) -.9 +1
v = 0.55 . . . . . value of minimum velocity