Answer:
9.0×10^3K/moles
Step-by-step explanation:
ionization energy of these electrons = Energy of photons - kinetic energy of the electrons
Given
Kinetic energy of electron = 1.34×10^5
Energy of photons = 1.43 x 105 kJ/mole
Required
Ionization energy of these electrons
Ionization energy of these electrons = 1.43×10^5-1.34×10^5
ionization energy of these electrons = 0.09×10^5 kJ/mol
= 9.0 × 10^3 kJ/mol
Hence the ionization energy of these electrons is 9.0×10^3K/moles
