Question

15. A photoelectron experiment is performed on a sample of silicon using photons with an energy

Answer 1

Answer:

9.0×10^3K/moles

Step-by-step explanation:

ionization energy of these electrons = Energy of photons - kinetic energy of the electrons

Given

Kinetic energy of electron = 1.34×10^5

Energy of photons = 1.43 x 105 kJ/mole

Required

Ionization energy of these electrons

Ionization energy of these electrons = 1.43×10^5-1.34×10^5

ionization energy of these electrons = 0.09×10^5 kJ/mol

= 9.0 × 10^3 kJ/mol

Hence the ionization energy of these electrons is 9.0×10^3K/moles