That's not true at all.
If a=2 and b=3 . . . then
2 · a · b = 12
but
a² + b² = 13 .
This doesn't satisfy your statement, because 12 and 13 are not equal.
Right off hand, it looks to me as if your statement is true
ONLY if
|a| = |b| ('a' = plus or minus 'b')
and NOT for any other pairs of numbers.
<span> The quadratic formula says that any quadratic equation of the form ax^2 + bx + c, then
x=(-b ± √(b^2 - 4ac))/2a, and so because of the square root, theres
obviously going to be no x-intercepts if b^2 - 4ac is negative, one
x-intercept if its zero, or two if its positive. So to calculate the
discriminant, which is whether it has an intercept, no intercepts or two
intercepts is:
∆=b^2 - 4ac, where delta, the greek equivalent of D, is used to represent the discriminant.
In the above equation a=-4, b=3 and c=-2, so
∆=3^2 - 4*-4*-2=9 - 32=-23, so because the discriminant is negative, then there are no x-intercepts.
This is from
https://answers.yahoo.com/question/index;_ylt=A0LEVvH2KJ5Y8UMAhHwPxQt.;_ylu=X3oDMTByMjB0aG5zBGNvbG8D...
</span>
Add them then take away 20
Answer:
16
Step-by-step explanation:
the numbers are divided by 4 to form a sequence so 64 divided by 4 is 16
