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Scorpion4ik [409]
3 years ago
9

During an acid/base titration, Timothy was using a burette. In order to determine the volume of titrant added, Timothy needed to

read and record the initial burette reading before beginning the titration and the final reading after reaching the end point of the titration. While recording these measurements, Tom was incorrectly reading the top of the meniscus. Will this systematic error influence his result? Why or why not?
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

The answer to the question is

The error due to taking measurement from the top will lead to an overestimation of the reagent by up to  0.08 cm³ where the maximum error in each measurement of a burette is 0.5 cm³, therefore the error is within acceptable limits.

Explanation:

The meniscus of the liquid is the shape of the surface of a liquid as observed when the liquid is in narrow container such as in a burret. The shape of the meniscusis due to the effect of surface tension.

When taking measurements from a burette, it is important that the eye should be at the same level as that of the meniscus with the reading taking from the bottom of the meniscus

The error of reading from the top of the burette instead of the bottom is a form of parallax error

The maximum error allowed in burette measurement is 0.05 cm³ while the error of reading from the top leads to an error of 19.70 -  19.62 = -0.08 l which is equivalent to -0.08 cm³

The error is within the acceptable limits but it could be larger and impact on the results of experiments as there would be

1. Less reagent to complete a chemical reaction

2. Different rate of reaction

3. Wastage of reagents

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What happens to the atoms during a chemical reaction
Likurg_2 [28]

Answer:

Atoms get rearranged and make up different molecules. No atoms are created nor destroyed.

Explanation:

6 0
2 years ago
Ephedrine, a central nervous system stimulant, is used in nasalsprays as a decongestant. this compound is a weak organic base: {
sashaice [31]

Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base:

C10H15ON (aq) + H2O (l) -> C10H15ONH+ (aq) + OH- (aq)

A 0.035 M solution of ephedrine has a pH of 11.33.

a) What are the equilibrium concentrations of C10H15ON, C10H15ONH<span>+, and OH-</span>?

b) Calculate <span>Kb</span> for ephedrine.

c(C₁₀H₁₅NO) = 0,035 M.<span>
pH = 11,33.
pOH = 14 - 11,33 = 2,67.
[OH</span>⁻] = 10∧(-2,67) = 0,00213 M.<span>
[OH</span>⁻] = [C₁₀H₁₅NOH⁺] = 0,00213 M.<span>
[</span>C₁₀H₁₅NO] = 0,035 M - 0,00213 M = 0,03287 M.<span>
Kb = [OH</span>⁻] · [C₁₀H₁₅NOH⁺] / [C₁₀H₁₅NO].<span>
Kb = (</span>0,00213 M)² / 0,03287 M = 1,38·10⁻⁴.

3 0
4 years ago
Every conversion factor is a ratio that is<br> equal to 1<br> less than 1<br> greater than 1
miss Akunina [59]

equal to 1

Explanation:

All conversion factors used in any calculation is usually a ratio that is equal to 1. This is because when 1 is used to multiply or divide any number, the number stays the same.

  • Conversion factors are useful in making the simplification of an expression very simple. They are usually ratios of 1.
  • It follows that a conversion factor is a number that when multiplied or divided by itself will stay the same.

Learn more:

conversion factor: brainly.com/question/555814

#learnwithBrainly

4 0
4 years ago
Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.
padilas [110]

The calculated enthalpy of formation of kerosene is 365.4 kJ and heat produced is 78650.3 kJ

For this, we need the normal enthalpy of formation given below

ΔH∘f(CO2)=−393.5kJ/molΔH∘f(H2O)\s=−241.8kJ/molΔH∘f(O2)=0kJ/mol

We shall now determine the enthalpy of kerosene formation:

H rxn = 24 mol H f (CO2) + 26 mol H f (H2O) + 2 mol H f (C12H26) + 37 mol H f (O2) + 1.50 104 kJ = 9444 kJ + 6286.8 kJ + 1500 kJ 2 mol H f (C12H26) = 730.8 kJ H f (C12H26) = 365.4 kJ

Kerosene has a density of 0.74 g/mL.

Kerosene volume (V) equals 0.63 gallons, or 0.63 x 3785.4, or 2384. 8 mL.

We shall now calculate the mass (m) of kerosene:

ρ=mVm\s=ρ×Vm\s=0.749g/mL×2384.mLm\s=1786.2g

We shall now discover the heat that 1786 generated.

Two grams of kerosene

Kerosene's molar mass is 170.33 g/mol.

The mass of two moles of kerosene is equal to 2*170.33*340.66g.

1.50104kJ of heat are generated by 340.66 g of kerosene.

1786 produced heat.

Kerosene 2 grams = 1.50 104 kJ 340.66 1786.2 g = 78650.3 kJ

Learn more about enthalpy here-

brainly.com/question/13996238

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5 0
1 year ago
Please help asap loll
BlackZzzverrR [31]

Explanation:

Metals -

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  4. Good conductor
  5. Mostly solid
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Non-metals -

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3 years ago
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