<span>S= (a+b)^2+(4a+b-2)^2+(9a+b-4)^2
98a+14b-44=0
14a+3b-6=0
a=24/49, b=-2/7
y = (24/49)x^2-(2/7)</span>
Given:
The given number is:

To find:
The product of prime factors of given number.
Solution:
We have,

The prime factors of given number are:
<u>2 | 96</u>
<u>2 | 48</u>
<u>2 | 24</u>
<u>2 | 12</u>
<u>2 | 6</u>
<u>3 | 3</u>
| 1
So, 96 can be written as:

Therefore, the 96 as the product of prime factors is
.
3x - 4 = <span>3(-3) - 4 = -9 - 4 = -13
</span>3x - 4 = <span>3(-1.4) - 4 = -4.2 - 4 = -8.2
answer
range { -13, -8.2}</span>
Answer:
quotient
Step-by-step explanation:
yup it just is
The answer is true. We know this because 9^2 - 6^2 is 45.