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True [87]
2 years ago
15

Which relationship describes angles 1 and 2?

Mathematics
1 answer:
stiks02 [169]2 years ago
6 0
They are vertical angles and here’s why.

Vertical angles are a pair of opposite angles formed by intersecting lines.

Supplementary angles are two angles that equal 180 when added together.

Adjacent angles are two angles that have a common side and a common vertex.

Complementary angles are two angles that add up to 90 degrees.

Hope this helped!
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Help!! - 2.10 - (4 points)
Brrunno [24]

Answer:

Approach: Difference of Squares Pattern

4 {x}^{2}  - 25 = (2x - 5)(2x + 5)

Step-by-step explanation:

The given binomial is:

4 {x}^{2}  - 25

We can rewrite to obtain:

{(2x)}^{2}  -  {5}^{2}

This is a difference of two squares, so we will factor using difference of squares pattern.

Recall that:

{a}^{2} -  {b}^{2}   = (a + b)(a - )

If we let

a = 2x

and

b = 5

Then we can factor the given binomial to obtain:

{2x}^2 -  {5}^{2}  = (2x - 5)(2x + 5)

\therefore4 {x}^{2}  - 25 = (2x - 5)(2x + 5)

6 0
3 years ago
How many T-shirt’s did he sell?
kumpel [21]
He sold 17 t-shirts. Subtract 40 from 125 and then divide 5 into 85. Your answer is 17.
7 0
2 years ago
PLEASE HELP!!
Musya8 [376]

Answer:

x = - 33

Step-by-step explanation:

Given

\frac{2}{3}(x + 6) = - 18

Multiply both sides by 3 to clear the fraction

2(x + 6) = - 54 ( divide both sides by 2 )

x + 6 = - 27 ( subtract 6 from both sides )

x = - 33

6 0
3 years ago
Read 2 more answers
I will give a thanks
gogolik [260]
Do what is in the parentheses then add
7 0
3 years ago
What is the equation of the quadratic graph with a focus of (1 ,3) and a directrix of y=1?
zimovet [89]
Check the picture below.

now, we know the directrix is at y = 1, and the focus point is at 1,3, well, notice the picture, the distance between those fellows is just 2 units.

the vertex is half-way between those fellows, therefore, the vertex will be at 1,2.

the distance "p", from the vertex to either the directrix or focus, is really just 1 unit.  Since the focus point is above the directrix, is a vertical parabola, and it opens upwards, like in the picture, and since it opens up, the "p" value is positive, or +1.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
4p(x- h)=(y- k)^2
\\\\
\boxed{4p(y- k)=(x- h)^2}
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ( h, k)\\\\
 p=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=1\\
k=2\\
p=1
\end{cases}\implies 4(1)(y-2)=(x-1)^2\implies 4(y-2)=(x-1)^2
\\\\\\
y-2=\cfrac{1}{4}(x-1)^2\implies y=\cfrac{1}{4}(x-1)^2+2

4 0
3 years ago
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