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True [87]
2 years ago
15

Which relationship describes angles 1 and 2?

Mathematics
1 answer:
stiks02 [169]2 years ago
6 0
They are vertical angles and here’s why.

Vertical angles are a pair of opposite angles formed by intersecting lines.

Supplementary angles are two angles that equal 180 when added together.

Adjacent angles are two angles that have a common side and a common vertex.

Complementary angles are two angles that add up to 90 degrees.

Hope this helped!
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_____ are birds which are famous for performing a ritualized mating dance.
padilas [110]
I do believe it’s D. Albatrosses
7 0
3 years ago
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The function below crosses the x-axis once. y=3x^2-8x+8
Mekhanik [1.2K]
I believe it is false because it only passes through the y-axis not the x-axis.

6 0
3 years ago
Use slopes and y-intercepts to determine if the lines 5x-5y=-2 and -x+2y=4
HACTEHA [7]

The given pair of lines are not perpendicular.

<h3>What is a line?</h3>

The line is a curve showing the shortest distance between 2 points.

5x - 5y = -2 - - - - - (1)
Transform the equation into standard form,
5x + 2 = 5y
y = 5x /5 + 2/5
y = x + 2/5


The slope of equation 1 is m_1 = 1  and intercept c = 2 / 5


Similarly
x + 2y = 4    - - - - - - - -(2)
Transform it into standard form
y = -x/2 + 4 /2
y = -x / 2 + 2


Slope of the equation 2  m_2= -1 / 2 and intercept c = 2
Slope of line 1 * slope of line 2 = 1 * -1/2 = -1/2


Since the lines are not perpendicular because the pair of lines does not satisfy the property of perpendicular lines i.e
m_1*m_2 = -1

Thus, the given pair of lines are not perpendicular.

Learn more about lines here:

brainly.com/question/2696693

#SPJ1  

6 0
1 year ago
Find the domain of ( (a+b/b) − (a/a+b))÷( (a+b/a) − (b/a+b) )
Alexandra [31]

Answer:

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, a=-b

Step-by-step explanation:

The domain refers to values for which the expression is defined.

This implies that, the denominators are not equal to zero.

(\frac{a + b}{b} -  \frac{a}{a + b}) \div ( \frac{a + b}{a} -  \frac{b}{a + b})

(\frac{(a + b)(a + b)-ab}{b(a + b)})\div(\frac{(a + b)(a + b)-ab}{a(a + b)})

\frac{(a + b)(a + b)-ab}{b(a + b)} \times\frac{a(a + b)}{(a + b)(a + b)-ab}

\implies \frac{a}{b}

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, and a=-b

7 0
3 years ago
Read 2 more answers
1 find the area in square cm of a square whose side is
lara [203]
For question 1:

Part i)

2.6 x 2.6 = 6.76 cm squared

No unit conversions needed

Part ii)

1.2 dm = 1.2 / 1000000 = 0.0000012 cm

0.0000012 x 0.0000012 = 0.00000000000144 cm squared

Question 2:

16.5dm = 16.5/ 1000 = 0.0165 m

0.0165 x 0.0165 = 0.00027225 m squared

I hope this has helped
3 0
3 years ago
Read 2 more answers
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