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enot [183]
2 years ago
13

3x-5y>20 what's the inequality for y

Mathematics
1 answer:
Alexeev081 [22]2 years ago
7 0

X<20-5y (the whole expression divided by 3)


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Bob drove from home to work at 75 mph.After work the traffic was heavier,and he drove home at 40 mph.His driving time to and fro
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Answer:

Bob drove from home to work at 75 mph. After work the traffic was heavier, and he drove home at 40 mph. His driving time to and from work was 1 hour and 9 minutes. How far does he live from his job?

=================

Avg speed for the round trip = 2*75*40/(75+40) = 6000/115 = 1200/23 mi/hr

RT distance = 1200/23 * 69 minutes * 1 hr/60 mins =

= 60 miles

30 miles each way

Step-by-step explanation:

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Step-by-step explanation:

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I don't understand this, please help ​
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Answer:

∠2 = 150°, it is a supplementary angle to 30°

∠3 = 30°, it is an alternate angle to 30°

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6 0
3 years ago
The rate of growth of profit​ (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati
Alecsey [184]

Answer:

The function is  P(x) =  \frac{1}{2} e^{-x^2} +0.016

Step-by-step explanation:

From the question we are told that

    The rate of growth  is  P'(x) =  xe^{x} - x^2

     The total profit is P(2)  =$25,000

      The time taken to make the profit is x =  2 \ years

         

From the question

     P'(x) =  xe^{-x^2}  is the rate of growth

  Now here x represent the time taken

Now the total profit is mathematically represented as

       P(x) =  \int\limits {P'(x)} \,  =   \int\limits {xe^{-x^2}} \,

So using substitution method

   We have that

                      u =  - x^2

                      du =  2xdx

  So  

        p(x) =  \int\limits {\frac{1}{2} e^{-u}} \, du

       p(x) =  {\frac{1}{2} [ e^{-u}} +c ]

       p(x) =  {\frac{1}{2}  e^{-x^2}} + \frac{1}{2} c      recall  u =  - x^2   and  let  \frac{1}{2} c =  Z

       

At  x =  2 years  

     P(x)  =$25,000

So

       Since the profit rate is in million

    P(x)  =$25,000 = \frac{25000}{1000000} =$0.025 millon dollars

So  

       0.025 =  {\frac{1}{2}  e^{-2^2}} + Z  

=>    Z = 0.025 - {\frac{1}{2}  e^{-2^2}}  

       Z = 0.016  

So the profit function becomes

         P(x) =  \frac{1}{2} e^{-x^2} +0.016

     

       

5 0
3 years ago
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