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Serggg [28]
3 years ago
10

Calculate the concentration of the following solution in mol/dm3 0.1 moles of NaCl in 200 cm3

Chemistry
1 answer:
taurus [48]3 years ago
8 0
1 cm ^{3} = 0.001 dm ^{3}. Therefore 200 cm ^{3} = 0.2 dm ^{3}. Molarity = \frac{number of moles of NaCl}{volume of the solution} =  \frac{0.1}{0.2} = 0.5 mol/dm^{3}. Hope this helps.
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Each of the following values was read on an instrument of measuring device. In each case the last digit was estimated. Tell what
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<h3>160 cm</h3>

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3 years ago
Which of the following best describes how an ionic compound dissolves in water?
Nadusha1986 [10]

The statement that best describes how an ionic compound dissolves in water is as follows: it separates into individual molecules and is an electrolyte, which is option C.

<h3>What is an ionic compound?</h3>

Ionic compound is any compound is a chemical compound composed of ions (charged atoms) held together by electrostatic forces termed ionic bonding.

Ionic compounds are electrolytes i.e. a substance when, in solution or when molten, ionizes and conducts electricity.

For example; sodium chloride (NaCl) is an ionic compound breaks down into sodium ions (Na+) and chloride ion (Cl-).

Therefore, the statement that best describes how an ionic compound dissolves in water is as follows: it separates into individual molecules and is an electrolyte.

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4 0
2 years ago
A rotameter calibration curve (flow rate versus float position) obtained using a liquid is mistakenly used to measure a gas flow
Veronika [31]

Answer:

I would expect the gas rate determined in this manner to be too low

Explanation:

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5 0
3 years ago
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Bess [88]
This is not a question
what are you asking
8 0
3 years ago
Read 2 more answers
Determine the empirical formula of a compound containing 1.71 g of silicon and 8.63 g of chlorine.
Basile [38]

Answer:

The answer to your question is: SiCl₄

Explanation:

Data

amount of Si      1.71 g

amount of Cl     8.63 g

MW Si = 28 g

MW Cl = 35.5

Process (rule of three)

For Si                                                        For Cl

        28 g of Si ------------------ 1 mol                      35.5 g of Cl --------------- 1 mol

          1.71g of Si  ---------------   x                              8.63 g of Cl --------------  x

         x = 1.71 x 1 / 28 = 0.06 mol                          x = 8.63 x 1 / 35.5 = 0.24 mol

Now, divide both results by the lowest of them.

Si = 0.06 mol / 0.06 = 1 molecule of Si     Cl = 0.24 / 0.06 = 4 molecules of Cl

Finally

                     Si₁ Cl₄ or SiCl₄

8 0
3 years ago
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