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3 years ago

10

Calculate the concentration of the following solution in mol/dm3 0.1 moles of NaCl in 200 cm3

1 answer:

taurus [48]3 years ago

8 0

1 $cm ^{3}$ = 0.001 $dm ^{3}$ . Therefore 200 $cm ^{3}$ = 0.2 $dm ^{3}$ . Molarity = $\frac{number of moles of NaCl}{volume of the solution} = \frac{0.1}{0.2} = 0.5 mol/dm^{3}$ . Hope this helps.

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Answer:

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Complete Question

The complete question is shown on the first uploaded image

Answer:

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