Question

Calculate the concentration of the following solution in mol/dm3 0.1 moles of NaCl in 200 cm3

Answer 1

1 $cm ^{3}$ = 0.001 $dm ^{3}$. Therefore 200 $cm ^{3}$ = 0.2 $dm ^{3}$. Molarity = $\frac{number of moles of NaCl}{volume of the solution} = \frac{0.1}{0.2} = 0.5 mol/dm^{3}$. Hope this helps.