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3 years ago

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Which best describes the role of a primary consumer in a food web? Carnivore that feeds on producers Herbivore that feeds on pro

ducers Herbivore that feeds on primary consumers Carnivore that feeds on primary consumers

1 answer:

lina2011 [118]3 years ago

6 0

A primary consumer is a herbivore that feeds on producers. They are the first in the food chain to eat making them the primary consumers.

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determine mass of water formed when 12.5 L NH3(at298K and 1.50atm) is reacted with 18.9L of O2 (at 323K and 1.1atm)

sasho [114]

The mass of water formed is

<u><em>calculation</em></u>

Use the ideal gas equation to calculate the moles of NH3 and O2

that is Pv= n RT

where; P= pressure,

V= volume,

n = number of moles,

R=gas constant = 0.0821 l .atm/ mol.K

make n the formula of the subject by diving both side by RT

n = PV /RT

The moles of NH3

n= (1.50 atm x 12.5 L) /( 0.0821 L. atm /mol.k x 298 K) =0.766 moles

The moles of O2

=(1.1 atm x 18.9 L) / ( 0.0821 L. atm/ mol.k x 323 K) = 0.784 moles

write the reaction between NH3 and O2

4 NH3 + 5 O2 →4 No +6H2O

from equation above 0.766 moles of NH3 reacted to produce

0.766 x 6/4 =1.149 moles of H2O

0.784 moles of O2 reacted to produce 0.784 x 6/5=0.9408 moles of H20

since O2 is totally consumed, O2 is the limiting reagent and therefore the moles of H2O produced= 0.9408 moles

mass of H2O = moles x molar mass

from periodic table the molar mass of H2O = (1 x2)+16= 18 g/mol

mass = 18 g/mol x 0.9408 moles= 16.93 grams

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3 years ago

PLEASE HELP 50 POINTS A really colorful reaction is the synthesis reaction of aluminum and iodine, often called the “Purple Haze

marysya [2.9K]

Answer:

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mestny [16]

Answer:

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Explanation:

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A chemist has some 40% acid solution, some 60% acid solution, and a wholebunch of free time. How many liters of each should be u

TiliK225 [7]

Answer:

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Explanation:

Let volume of the 40% acid solution be x.

Let volume of the 60% acid solution be y.

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x + y = 40 L..[1]

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Volume of acid 60% solution = 60% of y= 0.6y

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Answer:

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