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aleksklad [387]
3 years ago
12

How many colors would you see if you were analyzing a pure substance through chromatography?

Chemistry
2 answers:
harina [27]3 years ago
4 0

Answer :

The correct answer is  no color will observed if a pure substance is analyzed ,

Chromatography :

It is a technique commonly used to separate a mixture of chemical substances based on their affinity with stationary phase and mobile phase .

The  mobile phase travels through the stationary phase  in a definite direction . The component of mixture travels along with mobile according to their affinity , ionic interactions , diffusion , solubility  on stationary phase .

The component has more affinity with mobile phase goes higher with mobile phase .

While component with stationary phase remain at lower position  on stationary phase .

This is how separation of components takes place.

A pure substance has only one type of component in it . There is no mixture of components.

Hence when pure substance will be analyzed  by chromatography technique, there will be no separation of components .

So there will no color  be observed.  

AfilCa [17]3 years ago
3 0

For separation of components of mixture chromatography technique is used. Parts of mixture are separated by using the different solubilities of the parts for a stationary phase (that does not move) compared to the mobile phase (that carries the parts). Due to capillary action, the solvent will move up with paper or plate in apparatus.  The mobile phase will move with solvent and the stationary phase will remain adhere to the paper or plate. And thus, giving separate colors for the substances present in the mixture.

Hence, for pure substance, only one color would be observed through chromatography.

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When NEM is added to a purified solution of creatine kinase, Cys 278 is alkylated, but no other Cys residues in the protein are
USPshnik [31]

Answer:

The answer is given below

Explanation:

Cys 278 residue is the only available cysteine which is alkylated  by the addition of N-Ethylmaleimide or NEM (alkylating agent). It works by only alkylating the sulfhydryls. In this case, Cys 278 residue is the only one which has exposed cysteine residue.

While the other residues have their sulfhydryls group either involved in the synthesis of disulfide bonds of proteins or their Cys residues are intrinsically placed in the proteins and cannot be alkylated with NEM.

NEM cannot alkylate if its protein is not available in the free form or it is in bounded form. For NEM to alkylate Cys 278, it should be free and should have sulfhydryls available for alkylation.

Alkylation: it is the transfer of alkyl groups. Alkyl groups contain Hydrogen and Carbon in their structure.

5 0
4 years ago
The Sun is a yellow star that's both average in brightness and temperature and is classified as
Roman55 [17]

Answer:

Classifying stars according to their spectrum is a very powerful way to begin to understand how they work.  As we said last time, the spectral sequence O, B, A, F, G, K, M is a temperature sequence, with the hottest stars being of type O (surface temperatures 30,000-40,000 K), and the coolest stars being of type M (surface temperatures around 3,000 K).  Because hot stars are blue, and cool stars are red, the temperature sequence is also a color sequence.  It is sometimes helpful, though, to classify objects according to two different properties.  Let's say we try to classify stars according to their apparent brightness, also.  We could make a plot with color on one axis, and apparent brightness on the other axis, like this:

Explanation:

7 0
3 years ago
Why do atoms usually combine?
Alexandra [31]

Answer:

Most interactions among atoms take place in the outermost shell of each atom. The number of each electron in this shell determines how an atom combines with other atoms to form compounds. When atoms combine they gain, lose or share electrons in such a way that the outer shells become chemically complete.

Explanation:

3 0
4 years ago
Lactic acid has a pKa of 3.08. What is the approximate degree of dissociation of a 0.35 M solution of lactic acid?
aalyn [17]

The approximate degree of dissociation of a 0.35 M solution of lactic acid is 4,87%

<h3>What is  degree of dissociation?</h3>

The degree of dissociation is the quantity used to express the strength of a base, that is, its ability to conduct electric current, which depends on the amount of ions released in the dissociation.

The degree of dissociation (α) is another way of determining the strength of a base. It indicates the fatty acids that were released from a base when it dissociates in water.

With that being said, C stands for concentration and α is the the degree of dissociation.

Latic Acid can be written as  C3H6O3

CH3Ch(OH)CO2H < -- > H^{+} + CH3CH(OH)CO2^{-}

Ka = \frac{[H^{+}] [CH3CH(OH)CO2^{-}]  }{CH#CH(OH)CO2H} = \frac{C^{2} \alpha^{2}  }{C(1-\alpha )} = \frac{C\alpha ^{2} }{(1-\alpha )}

As α is too small (1-α) can be neglected.

Ka = C\alpha ^{2}  \\\\\\alpha    = \sqrt[]{\frac{Ka}{C} }

Ka = 10^{-3,08}  = 8,32 .10^{-4} .10^{-4} = 0,35

\alpha = \sqrt{\frac{ka}{C} } \\\\\alpha = \sqrt{\frac{8,32.10^{-4} }{0,35} } = 0,0487

In this case, is possible to see that  approximate degree of dissociation of a 0.35 M solution of lactic acid is 4,87%

See more about pKa at: brainly.com/question/14924722

#SPJ1

5 0
2 years ago
The observed rotation of 2.0 gg of a compound in 50 mLmL of solution in a polarimeter tube 25-cmcm long is +47.2 ∘∘ . What is th
Anastaziya [24]

Answer:

[∝] = +472

Explanation:

Specific rotation in a solution is defined as:

[∝] = ∝ / c×l

Where:

[∝] is specific rotation, ∝ is observed rotation (In degrees), c is concentration in g/mL and l is path length (In dm).

∝: +47.2°

c: 2.0g / 50mL = 0.04g/mL

l: 25cm × (1dm /10cm) = 2.5dm

Replacing:

[∝] = +47.2° / 0.04g/mL×2.5dm = <em>+472</em>

I hope it helps!

4 0
3 years ago
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