Answer:
The speed of the boxes are 1 m/s.
Explanation:
Given that,
Mass of box = 1 kg
Mass of another box = 2 kg
Suppose 1 kg box moves with 3 m/s speed.
We need to calculate the speed of the boxes
Using formula of conservation of momentum
Where, u = initial velocity
v = final velocity
Put the value into the formula
Hence, The speed of the boxes are 1 m/s.
Answer:
in a magnet there is a magnetic field that draws ever mental to it
Answer:
t = 2.13 s
Explanation:
given,
height of the building = 22.3 m
horizontal distance = 127 m
acceleration due to gravity = 9.8 m/s²
time for which ball is in motion = ?
using equation of motion
initial velocity is zero
t = √4.551
t = 2.13 s
Answer:
The correct answer is dissolving and the end product is a solution.
Explanation:
Solubility is an property of a substance to get dissolved into another. When a substance, termed as solute, dissolves in another substance, termed as solvent, we get a solution.
Larger molecules of the solute breaks because of weak covalent bonds between their molecules and pairs up with the smaller molecules of the solvent and thus dissolves in it. Not all elements can serve solutes or solvents as some have strong forces that bind them together. For example sugar is a solute in water but oil is not soluble in water.
Answer:
RL=100K → Vo=9.90 mV
RL=10K → Vo=9.09 mV
RL=1K → Vo=5 mV
RL=100 → Vo=909.09 μV
In order to obtain 80% of the power source we have to put a resistor of 4 KOhm.
Explanation:
Here we have a power source in serie with a resistor of 1K and RL, in order to obtain the Vo voltage we have to apply the voltage divider rule, that states:
Substituing the resistor values of RL we obtained the following results:
RL=100K → Vo=9.90 mV
RL=10K → Vo=9.09 mV
RL=1K → Vo=5 mV
RL=100 → Vo=909.09 μV
In order to find the lowest value that gives us 80% of the source voltage we have to use the voltage divider rule again and make the Vo equal to 0.8 Vin:
The result of the last equation is 4000, so in order to obtain 80% of the power source we have to put a resistor of 4 KOhm.