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marshall27 [118]
3 years ago
7

Two forces one of 12N and another of 5N act on abody in such away that they makes an angel of 90 with each other, what is the re

sultant
Physics
1 answer:
Murljashka [212]3 years ago
6 0

Answer:

13 N

Explanation:

From the question,

If two forces act at right angle to each other, Their result force can be calculated using Pythagoras theorem.

R'² = R₁²+R₂²....................... Equation 1

Where R' = Resultant force, R₁ = First force, R₂ = Second force.

Given: R₁ = 12 N, R₂ = 5 N

Substitute these values into equation 1

R'² = 12²+5²

R'² = 144+25

R'² = 169

R' = \sqrt{169}

R' = 13 N.

Hence the resultant force is 13 N

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Object A has a mass of 10 kg and is moving at a velocity of 2.0
luda_lava [24]

Answer:20kgm/s

Explanation:

Mass=10kg

Velocity=2m/s

Momentum=mass x velocity

Momentum=10 x 2

Momentum=20

Momentum=20kgm/s

4 0
2 years ago
The period T of a simple pendulum depends on the length L of the pendulum and the acceleration of gravity g (dimensions L/P). (a
andriy [413]

Answer:

a). L= meters, g= \frac{m}{s^{2} }

b). L= 5cm  T=0.448

    L= 10 m  T=6.34

c).  Constant= \frac{2*\pi }{\sqrt{g} }=\frac{2*\pi }{\sqrt{9.8} }=2.007089923

Explanation:

a).

T= 2*\pi  \sqrt{\frac{L}{g} } = 2*\pi \sqrt{\frac{m}{\frac{m}{s^{2} } } } \\T= 2*\pi \sqrt{\frac{s^{2}*m }{m} }=2*\pi  \sqrt{s^{2}  } \\T= s

b).

L_{1}= 5 cm, 5cm *\frac{1m}{100 cm} = 0.05 m

T=2*\pi \sqrt{\frac{L}{g} }

T=2*\pi \sqrt{\frac{0.05}{9.8} }= 0.448s

L_{1}= 10 m

T=2*\pi \sqrt{\frac{L}{g} }

T=2*\pi \sqrt{\frac{10}{9.8} }= 6.43s

c).

g= 9.8 \frac{m}{s^{2} }

T=2*\pi *\frac{\sqrt{L} }{\sqrt{g} } =T=2*\pi *\frac{\sqrt{L} }{\sqrt{9.8} } \\T= 2*\pi \frac{1}{\sqrt{9.8}} *\sqrt{L}\\T= 2.007089923*\sqrt{L}

6 0
2 years ago
A uniformly charged sphere has a potential on its surface of 450 V. At a radial distance of 8.1 m from this surface, the potenti
igomit [66]

Answer:

The radius of the sphere is 4.05 m

Explanation:

Given;

potential at surface, V_s = 450 V

potential at radial distance, V_r = 150

radial distance, l = 8.1 m

Apply Coulomb's law of electrostatic force;

V = \frac{KQ}{r} \\\\V_s = \frac{KQ}{r} \\\\V_r = \frac{KQ}{r+ l}

450 = \frac{KQ}{r} ------equation (i)\\\\150 = \frac{KQ}{r+8.1} ------equation (ii)\\\\divide \ equation (i)\ by \ equation \ (ii)\\\\\frac{450}{150} = (\frac{KQ}{r} )*(\frac{r+8.1}{KQ} )\\\\3 = \frac{r+8.1}{r}  \\\\3r = r + 8.1\\\\2r = 8.1\\\\r = \frac{8.1}{2} \\\\r = 4.05 \ m

Therefore, the radius of the sphere is 4.05 m

4 0
2 years ago
Describe the radioactive disintegration’s known as alpha, beta, and gamma decay
I am Lyosha [343]
What’s the question
5 0
3 years ago
the mass of a brick is 4 kg, find the mass of water displaced by it when completely immersed in water.​
vova2212 [387]

Answer:

The correct answer is = 1.6

Explanation:

Density of water = 1000kg/m³ = d₁

Mass of brick = 4kg = m

Density of brick = 2.5 g/cm³ = 2.5 × 1000 =2500 kg/m³ = d₂

Volume of brick = m/d₂ = 4/2500 =16/10000 = 0.0016 L = v

Buoyant Force = v × d₁ × g          (g= acceleration due to gravity =9.8m/s²)

= 0.0016 × 1000 × 9.8 = 15.68 Newtons

By the Archimedes' Principle, the buoyant force is equal to the weight of the liquid displaced by an object.

Weight of the water displaced=Buoyant Force

=Mass of water displaced × g,

as weight = mass × acceleration due to gravity

15.68= mass of brick × 9.8

15.68/9.8 =Mass of water displaced

1.6 kg = Mass of water displaced

4 0
3 years ago
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