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3 years ago

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Firlakuza [10]3 years ago

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Jennifer, who has a mass of 50.0 kg, is riding at 35.0 m/s in her red sports car when she must suddenly slam on the brakes to av

Assoli18 [71]

Answer:

Average force = 3.5 kN

Explanation:

Given:

Mass of Jennifer (m) = 50 kg

Initial velocity = 35 m/s

Time taken to stop body = 0.5 s

Find:

Average force

Computation:

v = u + at

0 = 35 + a(0.5)

Acceleration (a) = - 70 m/s² = 70 m/s²

Average force = ma

Average force = (50(70)

Average force = 3500 N

Average force = 3.5 kN

6 0

3 years ago

A mass of 6 kg with initial velocity 16 m/s travels through a wind tunnel that exerts a constant force 8 N for a distance 1.6 m.

strojnjashka [21]

Answer:

$D=99.4665307m \approx 99.5m$

Explanation:

From the question we are told that

Mass $m=6kg$

Velocity of mass $V_m=16$

Force of Tunnel $F_t=8N$

Length of Tunnel $L_t=1.6$

Height of frictional incline $H_i=2.9$

Angle of inclination $\angle =16 \textdegree$

Acceleration due to gravity $g=9.8m/s^2$

First Frictional surface has a coeﬃcient $\alpha_1 =0.21\ for\ d_c=1$

Second Frictional surface has a coeﬃcient $\alpha _2=0.1$

Generally the initial Kinetic energy is mathematically given by

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}(6)(16)^2$

$K.E=768$

Generally the work done by the Tunnel is mathematically given as

$w_t=F_t*d_t$

$w_t=8*1.6$

$w_t=12.8J$

Therefore

$Total energy\ E_t=Initial\ kinetic energy\ K.E*Work done\ by\ tunnel\ W_t$

$E_t=K.E+E_t\\E_t=768J+12.8J$

$E_t=780.8J$

Generally the energy lost while climbing is mathematically given as

$E_c=mgh$

$E_c=(6)(9.8)(2.9)$

$E_c=170.52J$

Generally the energy lost to friction is mathematically given as

$E_f=\alpha *m*g*cos\textdegree*d_c$

$E_f=0.21*6*9.8*cos16*1$

$E_f=11.86965942 \approx 12J$

Generally the energy left in the form of mass $Em$ is mathematically given as

$E_m=E_t+E_c+E_f$

$E_m=(768J)-(170.52)-(12)$

$E_m=585.48J$

Since

$E_m=\alpha_2*g*m*d$

Therefore

It slide along the second frictional region

$D=\frac{585.46}{0.1*9.81*6}$

$D=99.4665307m \approx 99.5m$

6 0

3 years ago

A shark travels with an average velocity of 12 m/s s. How long (time) would it take the shark to swim 42 m at that velocity

liq [111]

Answer:

<em>t=3.5 seconds</em>

Explanation:

<u>Moving at Constant Speed</u>

Let's suppose and object travels in a constant direction and covers the same distances x at the same time t, we say it has a constant speed. It can be computed as:

$\displaystyle v=\frac{x}{t}$

The time taken to go through the distance x is computed by

$\displaystyle t=\frac{x}{v}$

Our shark moves at v=12 m/s and we need to compute the time it takes to swim x=42 m, so we have

$\displaystyle t=\frac{42}{12}$

$\boxed{t=3.5\ seconds}$

It takes the shark 3.5 seconds to swim 42 m

5 0

4 years ago

What is the direction of a vector with an x component of -12 m and a y component of 21 m?

Svet_ta [14]

Answer:

$Direction= 119.74^\circ$

Explanation:

<u>Displacement Vector</u>

The displacement, as every vector, has a magnitude r and a direction angle θ measured from the positive x-axis.

If we know the x-y components of the displacement, the magnitude and angle can be calculated by the equations:

$r=\sqrt{x^2+y^2}$

$\displaystyle \tan\theta=\frac{y}{x}$

The coordinates of the given vector are x=-12 m, y=21 m, thus:

$\displaystyle \tan\theta=\frac{21}{-12}=-1.75$

$\theta=tan^{-1}(-1.75)=-60.26^\circ$

Since the vector lies in the second quadrant, we add 180° to find the correct direction:

$\boxed{Direction=-60.26^\circ+180^\circ= 119.74^\circ}$

4 0

3 years ago

A spring that has a spring constant of 440 N/m exerts a force of 88 N on a box. What is the displacement of the spring? 0. 2 m 5

mina [271]

The displacement of a spring is directly proportional to the applied force. The displacement of the given spring is 50.45 m.

<h2></h2><h2>From Hooke's law:</h2>

$F = kx$

Where,

$F$ - force applied = 88 N

$k$ - spring constant = 440 N/m

$x$ - displacement = ?

Put the values in the formula,

$88 = 440 \times x\\\\x = \dfrac {440 }{88}\\\\x = 50.45 \rm \ m$

Therefore, the displacement of the given spring is 50.45 m.

Learn more about Hooke's law:

brainly.com/question/3355345

6 0

3 years ago