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natta225 [31]
4 years ago
14

#5) HELP WITH QUESTION!!!! MARKING BRAINLIEST!!! :)

Mathematics
1 answer:
Furkat [3]4 years ago
4 0
I think it’s the 3rd answer
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Which statement accurately describes how to perform a 90° counterclockwise rotation of point A (−1, −2) around the origin? Creat
Anastaziya [24]

Answer:

last one

Step-by-step explanation:

You are swinging A(-1,-2) around the center which in this case is the origin. Keep in mind that points on a circle all have a equal distance from the origin.  We don't want the distance from the center to change.

We want the center of that circle to be the origin.

So the answer is the last one:

"Create a circle with the origin as its center and a radius of the origin and point A, then locate a point on the circle that is 90° counterclockwise from point A. ​"

8 0
3 years ago
Read 2 more answers
Please help !!!! I want to pass
inna [77]

Answer:

51.3

Step-by-step explanation:

I will upload a photo soon, but it is from trig, and inverse cos.

6 0
4 years ago
Factorise (x+y)^3- (x^3+y^3) plzzz answer ​
lilavasa [31]

Answer:

\huge \boxed{ \boxed{ \tt 2xy(x + y)}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • factoring
  • PEMDAS
<h3>tips and formulas:</h3>
  • (a+b)³=a³+3a²b+3ab²+b³
  • a³+b³=(a+b)(a²-ab+b²)
<h3>let's solve:</h3>
  1. \sf \: use \: 2nd \: formula \: to \: simplify :  \\  \sf(x + y {)}^{3}  - (x + y)( {x}^{2}  - xy +  {y}^{2} )
  2. \sf factor \: out \: (x + y) :  \\ (x + y )\{(x + y)^{2} - ( {x}^{2}  - xy +  {y}^{2}  \}
  3. \sf simplify :  \\ (x + y {)} \{ {x}^{2}  + 2xy +  {y}^{2}  -  {x}^{2}  + xy -  {y}^{2}  \}
  4. \sf collect \: and \: combine \: like \: terms :  \\ (x + y) \{2xy \}
  5. \sf \: rewrite : \\  2xy(x + y)

and

we are done

5 0
3 years ago
Please help me answer this question.
GaryK [48]

Answer:

The answers are in the attachment

7 0
2 years ago
1. The difference of five times a number and 6 is -2.
OlgaM077 [116]

Answer:

13

Step-by-step explanation:

5-x+6=-2

X=13

5 0
3 years ago
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