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alexandr402 [8]
3 years ago
8

John invests a sum of money in a

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer: 0.000007638035

Step-by-step explanation:

We can use the formula for compound interest to solve this.

Now, the formula goes thus:

A = P ( 1 + r/n)^nt

Where A is the amount compounded, P is the initial amount I.e the principal, r is the rate in % , t is the time while n is the number of times the interest is compounded per time I.e how many times per year.

From the question, we get the following parameters, A = $1912.41 , P = ? , t = 15 years, r = 2.63% and n = 1 of course.

Now, we substitute these into the formula

1912.41 = P ( 1 + 2.63) ^ 15

1912.41 = P ( 3.63) ^ 15

1912.41 = P ( 250,379,850)

P = 1912.41 ÷ 250,379,850

P = 0.000007638035

Looks pretty funny an answer right?

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16 square inches.

Step-by-step explanation:

Split the shape into a rectangle and square. To solve for square, just mulitple the 2 sides (2 x 2) and you get an area of 4. To solve for the rectangle, you can multiple the 6 and 2 to get the area of 12. Add the 4 and 12 together and you get 16 square inches. Hope this helps!

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3 years ago
BRAINLIEST AWARD NO.2
zzz [600]

Answer:

A whole number first term to render as fifth term a value larger than 10000, should be at least 121

Step-by-step explanation:

The formula is given as recursive since it involves the previous number of the sequence, and defined as:

a_n=a_{n-1}*3+6

we also know that the first term is 4

Then in this case, the first five terms are:

a_1=4\\a_2=4*3+6=18\\a_3=18*3+6=60\\a_4=60*3+6=186\\a_5=186*3+6=564\\

So if we want to find the first term in the case that the fifth one is greater than 10,000 using this recursive formula, now we have to start backwards, and say that the fifth term is "> 10000" and what the fourth one is.

Notice that if you have this definition for the nth term, we can obtain from it, what the previous term is to find the general rule:

a_n=a_{n-1}*3+6\\a_n-6=a_{n-1}*3\\\frac{a_n-6}{3} = a_{n-1}\\a_{n-1}=\frac{a_n}{3} -2

So the rule is to subtract 6 from he term, and divide the subtraction by 3. Then working backwards:

a_5>10000\\\frac{a_5}{3} -2>\frac{10000}{3} -2\\a_4>=\frac{10000}{3} -2\\\frac{a_4}{3} -2>\frac{\frac{10000}{3}-2}{3}-2 =\frac{10000}{9}-\frac{8}{3} \\a_3>\frac{10000}{9}-\frac{8}{3} \\\frac{a_3}{3} -2>\frac{\frac{10000}{9}-\frac{8}{3} }{3} -2=\frac{10000}{27} -\frac{8}{9} -2=\frac{10000}{27} -\frac{26}{9}\\a_2=\frac{10000}{27} -\frac{26}{9}\\\frac{a_2}{3} -2>\frac{\frac{10000}{27} -\frac{26}{9}}{3} -2=\frac{10000}{81} -\frac{80}{27} \\a_1>\frac{10000}{81} -\frac{80}{27}\approx 120.49

therefore, the starting first term should be at least about 121 to give a fifth term larger than 10,000

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Answer:

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Step-by-step explanation:

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