Answer:
5x
Step-by-step explanation:
=> 6x-x
<u><em>Taking x common</em></u>
=> x(6-1)
=> x(5)
=> 5x
So we want to write a fraction that is less than 5/6 and has a denominator of 8. So lets start from 1/1 that is greater then 5/6 and doesn't have 8 as a denominator. Lets take one half from 1/1 and well get 1/2.
Answer:
dark brown and white
Step-by-step explanation:
Answer:
m^2+m+1
Step-by-step explanation:
- m^3 - 1= (m-1)(m^2+m+1)
- m^4 + m^2 + 1= m^4+2m^2+1 - m^2= (m^2+1)^2 -m^2= (m^2+m+1)(m^2-m+1)
- m^2+ m + 1
HCF= m^2+m+1 which is the factor of all three polynomials
Answer:
130
Step-by-step explanation:
The number of integers meeting the criteria can be found by counting them using a counting formula.
<h3>Divisible by 7</h3>
Integers divisible by 7 will have the form (7n), where n is some positive integer. The number of them less than 1000 can be found from ...
7n ≤ 1000
n ≤ 142.857
There are 142 integers less than 1000 that are divisible by 7.
<h3>Divisible by 7 and 11</h3>
Similarly, integers divisible by 7 and 11 will be of the form (77n), for some positive integer n.
77n ≤ 1000
n ≤ 12.987
There are 12 integers less than 1000 that are divisible by both 11 and 7.
<h3>Divisible by 7, not 11</h3>
The number of integers less than 1000 that are divisible by 7, but not 11, will be the difference of these numbers.
142 -12 = 130 integers divisible by 7, but not 11.
