In JKL and PQR, if JK PQ, KL QR, and K Q, then JKL must be congruent to PQR.
2 answers:
True!
Two shapes are congruent if when turning, flipping or sliding one shape it can become another. This problem is illustrated in the Figure below. So, you can see that we have two triangles ΔJKL and ΔPQR. As you can see:
- JK=PQ
- KL=QR
- ∠K=∠Q
Given that two sides are equal to two other sides and one angle is equal to another one, then JL= PR. Accordingly, since all the sides are congruent, then the whole triangle JKL is congruent to PQR
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(x - 8) and (x + 1), have when
x < - 8
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Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive
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Then
Answer:B