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3 years ago

In JKL and PQR, if JK PQ, KL QR, and K Q, then JKL must be congruent to PQR.

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

8 0

True!

Two shapes are congruent if when turning, flipping or sliding one shape it can become another. This problem is illustrated in the Figure below. So, you can see that we have two triangles ΔJKL and ΔPQR. As you can see:

JK=PQ
KL=QR
∠K=∠Q

Given that two sides are equal to two other sides and one angle is equal to another one, then JL= PR. Accordingly, since all the sides are congruent, then the whole triangle JKL is congruent to PQR

Svetlanka [38]3 years ago

3 0

Answer is True!

Apex

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3 years ago

The probability distribution for a

Yanka [14]

There are only two possible outcomes in the table that satisfy x ≤ -3; either x = -5 or x = -3. Then

P(x ≤ -3) = P(x = -5) + P(x = -3) = 0.17 + 0.13 = 0.3

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3 years ago

A construction zone on Interstate 15 has a speed limit of 40 mph. The speeds of vehicles passing through this construction zone

monitta

Answer:

a. The percentage of vehicles who pass through this construction zone who are exceeding the posted speed limit =90.82%

b. Percentage of vehicles travel through this construction zone with speeds between 50 mph and 55 mph= 2.28%

Step-by-step explanation:

We have to find

a) P(X>40)= 1- P(x=40)

Using the z statistic

Here

x= 40 mph

u= 44mph

σ= 3 mph

z=(40-44)/3=-1.33

From the z-table -1.67 = 0.9082

a) P(X>40)=

Probability exceeding the speed limit = 0.9082 = 90.82%

b) P(50<X<55)

Now

z1 = (50-44)/3 = 2

z2 = (55-44)/3= 3.67

Area for z>3.59 is almost equal to 1

From the z- table we get

P(55 < X < 60) = P((50-44)/3 < z < (55-44)/3)

= P(2 < z < 3.67)

= P(z<3.67) - P(z<2)

= 1 - 0.9772

= 0.0228

or 2.28%

3 0

3 years ago

How many permutations can be made with the letters in the word Metallica

pentagon [3]

<h3>Answer: 90720 </h3>

===============================================

Explanation:

There are 9 letters in "Metallica", so there would be 9! = 9*8*7*6*5*4*3*2*1 = 362880 different permutations; however, this is only the case if we could tell the letters L and A apart.

We have two copies of each of those repeated letters, so we have to divide by 2!*2! = (2*1)*(2*1) = 4 to account for these repeats.

Because we can't tell the repeated letters apart, we really have (9!)/(2!*2!) = (362880)/(4) = 90720 different permutations.

5 0

3 years ago

Quadrilateral QRST is a square. If the measure of angle RQT is 3x - 6. Find the value of x.

trapecia [35]

Given that quadrilateral QRST is a square.

Each angle of a square is of 90 degrees.

Angle <RQT is also an angle of 90 degrees.

We also given angle RQT = 3x - 6.

So, we can setup an equation as 3x-6 =90.

Now, we need to solve the equation for x.

6 is being subtracted from left side.

We always apply reverse operation. Reverse operation of subtraction is addition.

So, adding 6 on both sides of the equation, we get

3x-6+6 =90+6.

3x = 96.

3 is being multipied with x, in order to remove that 3, we need to apply reverse operation of multiplication.

So, dividing both sides by 3.

$\frac{3x}{3} = \frac{96}{3}$

x=32 (final answer).

3 0

3 years ago