This is a combustion reaction. Any reaction in which a hydrocarbon decomposes into carbon dioxide and water is classified as combustion. The energy used for the decomposition usually comes from intense heat, which is why combustion of a hydrocarbon almost always is associated with a source of fire.
Hello!
I'm going to have to infer that you meant "grams" and not "gallons" :-)
Anyways, to find the density, you need to the divide mass over volume (d = m/V).
Since we are given the volume being 15.0 mL, and the weight being 40.5 grams, we can find the density of the aluminum block.
40.5 grams / 15.0 mL = 2.7 g/mL
Therefore, the density of the aluminum block is 2.7 grams per milliliter.
A compound has more than 1 element that is bonded together. The only one listed that fits the definition is D
Explanation:
(6.1). The reaction equation will be as follows.
Assuming the value of 
as 
and let the solubility of each specie involved in this reaction is "s". The expression for will be as follows.
![K_{sp} = [Ba^{2+}][SO^{-}_{2}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BBa%5E%7B2%2B%7D%5D%5BSO%5E%7B-%7D_%7B2%7D%5D)
(Solids are nor considered)
= 
s = 
= 
= 
Therefore, solubility of barium sulfate in water is .
(6.2). As the molar mass of 
is 233.38 g/mol
Therefore, the solubility is g/L will be calculated as follows.
= 
Therefore, solubility of barium sulfate in grams per liter is .
