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VARVARA [1.3K]
3 years ago
11

What is the power output in an ac series circuit with 12.0 Ω of resistance, 15.0 Ω of inductive reactance, and 10.0 Ω of capacit

ive reactance, when the circuit is connected to a 120-V rms power supply
Physics
1 answer:
Bad White [126]3 years ago
7 0

Answer:

1022.485 Watt

Explanation:

resistance, R = 12 ohm

Inductive reactance, XL = 15 ohm

Capacitive reactance, Xc = 10 ohm

Vrms = 120 V

Power is given by

P = Vrms x Irms x CosФ

Where, CosФ is called power factor

CosФ = R / Z

Where Z is the impedance

Irms = Vrms / Z

So,

P = \frac{\left (V_{rms}^{2}\times R  \right )}{Z^{2}}

Z = \sqrt{R^2+\left ( X_{L}-X_{c} \right )^{2}}

Z = \sqrt{12^2+\left ( 15-10 \right )^{2}}

Z = 13 ohm

So,

P = \frac{\left (120^{2}\times 12  \right )}{13^{2}}

P = 1022.485 W

Thus, the power is 1022.485 Watt.

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