According to above question ~
- Current (I) = 4 Amperes
- Time (t) = 3 seconds
- Charge (q) = ?
Let's find the charge (q) by using formula ~
Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds
You construct a circuit containing some component C, along with other circuit elements. You want to simultaneously measure the c
urrent through C and the voltage across C while it remains connected to the rest of the circuit. Indicate where you would connect an ammeter (A) and a voltmeter (V) to perform these measurements. Fill any remaining gaps with wires as needed to complete the connection with the rest of the circuit.
1 answer:
Answer:
The position of the ammeter is in series down the component. While the voltmeter must be connected in parallel. Its position is the gap through the component C.
The positions of one or the other are indicated in the image.
Explanation:
An ammeter is defined as a device used to measure current. Its unit is the ampere. While a voltmeter is used in the measurement of the potential difference between two points. Its unit is the volt. The ammeter must be connected in series with the point at which the current is to be measured, while the voltmeter must be connected in parallel.
You might be interested in
Answer:
The right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²
Explanation:
Thickness of the wall is L= 20cm = 0.2m
Thermal conductivity of the wall is K = 2.79 W/m·K
Temperature at the left side surface is T₁ = 50°C
Temperature of the air is T = 22°C
Convection heat transfer coefficient is h = 15 W/m2·K
Heat conduction process through wall is equal to the heat convection process so
Expression for the heat conduction process is
Expression for the heat convection process is
Substitute the expressions of conduction and convection in equation above
Substitute the values in above equation
Now heat flux through the wall can be calculated as
Thus, the right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²