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nasty-shy [4]
3 years ago
14

Who wanna watch vore with me? give me your Instagram I will send you some vore

Physics
2 answers:
matrenka [14]3 years ago
7 0

Answer:

nnnnnnnahhhh thx for the points tho!

Explanation:

stepan [7]3 years ago
6 0

Answer:

What. Is. Vore.

Explanation:

Can. I. Get. Brainliest

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Why does a compass work differently on a moon then it would on earth
pogonyaev

A compass would work differently on the moon than the Earth because Earth's magnetic field is between 25,000 and 65,000 NanoTeslas. Whereas, the Moons magnetic field is about 2,500-6,500 and some parts of the moon have nonexistent magnetic fields.

8 0
3 years ago
. A projectile is launched from a cliff 100m above level ground with a velocity of 30m/s at an
trapecia [35]

Answer:

How to find the maximum height of a projectile?

if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...

if α = 45°, then the equation may be written as: ...

if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

7 0
3 years ago
A spring stretches 2.6 cm when a 7 g object is hung from it. The object is replaced with a block of mass 28 g which oscillates i
PSYCHO15rus [73]

Answer:

period = 0.65 sec

Explanation:

from the question we are given the following

extension (x) = 2.6 cm = 0.026 m

mass of object (Mo) = 7 g = 0.007 kg

mass of block (Mb) = 28 g = 0.028 g

acceleration due to gravity (g) = 9.8 m/s^{2}

period = 2π x \sqrt{\frac{Mb}{k}}

where k is the spring constant of the spring

and k = \frac{Mo x g}{x}

k =  \frac{0.007 x 9.8}{0.026}

k = 2.64 N/m

now period = 2π x \sqrt{\frac{0.028}{2.64}}

period = 0.65 sec

4 0
4 years ago
In Example 2.12, two circus performers rehearse a trick in which a ball and a dart collide. Horatio stands on a platform 6.4 m a
pickupchik [31]

Answer:

time of collision is

t = 0.395 s

h = 5.63 m

so they will collide at height of 5.63 m from ground

Explanation:

initial speed of the ball when it is dropped down is

v_1 = 0

similarly initial speed of the object which is projected by spring is given as

v_2 = 16.2 m/s

now relative velocity of object with respect to ball

v_r = 16.2 m/s

now since we know that both are moving under gravity so their relative acceleration is ZERO and the relative distance between them is 6.4 m

d = v_r t

6.4 = 16.2 t

t = 0.395 m

Now the height attained by the object in the same time is given as

h = v_2 t - \frac{1}{2}gt^2

h = 16.2(0.395) - \frac{1}{2}(9.81).395^2

h = 5.63 m

so they will collide at height of 5.63 m from ground

4 0
4 years ago
The two main states of mechanical energy are ___________ and potential energy.
shutvik [7]
<span>Potential energy and Kinetic energy</span>
6 0
3 years ago
Read 2 more answers
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