Answer:
<u><em>A.)</em></u> The particles that make up material A have more mass than the
particles that make up material B.
HOPE that helps!!! :)
Answer:
The workdone is 
Explanation:
From the question we are told that
The height of the cylinder is 
The face Area is 
The density of the cylinder is 
Where
is the density of freshwater which has a constant value

Now
Let the final height of the device under the water be 
Let the initial volume underwater be 
Let the initial height under water be 
Let the final volume under water be 
According to the rule of floatation
The weight of the cylinder = Upward thrust
This is mathematically represented as


So 
=> 
Now the work done is mathematically represented as

![= \rho_w g A [\frac{h^2}{2} ] \left | h_f} \atop {h}} \right.](https://tex.z-dn.net/?f=%3D%20%20%20%5Crho_w%20g%20A%20%5B%5Cfrac%7Bh%5E2%7D%7B2%7D%20%5D%20%5Cleft%20%7C%20h_f%7D%20%5Catop%20%7Bh%7D%7D%20%5Cright.)
![= \frac{g A \rho}{2} [h^2 - h_f^2]](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bg%20A%20%5Crho%7D%7B2%7D%20%20%5Bh%5E2%20-%20h_f%5E2%5D)
![= \frac{g A \rho}{2} (h^2) [1 - \frac{h_f^2}{h^2} ]](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bg%20A%20%5Crho%7D%7B2%7D%20%28h%5E2%29%20%20%5B1%20%20-%20%5Cfrac%7Bh_f%5E2%7D%7Bh%5E2%7D%20%5D)
Substituting values

Kinetic energy per unit of mass is

Given, 
Therefore,


Now potential energy per unit mass is

Given, 
Therefore,


Thus, total mechanical energy of the river water per unit mass is


OR

The net force on an object subject to friction is equal to the sum of the applied force and the frictional force.
Mathematically,

Here, m is mass of object and a is its acceleration. We take frictional force negative because it opposes the motion of object.
Given,
,
and 
Substituting these values in above formula, we get
.
Thus, the acceleration of an object is 
From my research, the question has the following choices:
a.the lowest frequency at which a standing wave is possible
b. the highest frequency at which s standing wave is possiblec. the only frequency at which a standing wave is possible
d. the only frequency at which standing wave is not possible
From there, the correct answer is A.