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andreev551 [17]
3 years ago
15

A car at a position 150 km [W] of Toronto travels to a position 400 km [W] of

Physics
1 answer:
tigry1 [53]3 years ago
6 0

Answer:

The total displacement of the car is 250 km.

Explanation:

Given that,

A car at a position 150 km [W] of Toronto travels to a position 400 km [W] of  Toronto.

Total displacement = final position - initial position

= 400 km - 150 km

= 250 km

So, the total displacement of the car is 250 km.

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A marble resting near the edge of .90 m high table is given an initial horizontal speed of 1.24 m/s. What will be it’s horizonta
Maru [420]

Answer:

0.53 m

Explanation:

First of all, we have to consider the vertical motion of the ball, in order to find the time it takes for the marble to reach the ground. The initial height is h=0.90 m, the initial vertical velocity is zero, while the acceleration is g=-9.81 m/s^2, so the vertical position at time t is given by

y(t)=h-\frac{1}{2}gt^2

By demanding y(t)=0, we find the time t at which the ball reaches the ground:

0=h-\frac{1}{2}gt^2

t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(0.9 m)}{9.81 m/s^2}}=0.43 s

Now we can find the horizontal range of the marble: we know the initial horizontal speed (v=1.24 m/s), we know the total time of the motion (t=0.43 s), and since the horizontal speed is constant, the total distance traveled on the horizontal direction is

x=vt=(1.24 m/s)(0.43 s)=0.53 m

8 0
3 years ago
What is the work done by the friction when the body slides against a rough horizontal surfaces?
katovenus [111]

Negative work

Hope this helps :)

4 0
2 years ago
A block of mass m=1.2 kg is held at rest against a spring with a force constant k=730N/m. Initially the spring is compressed a d
igor_vitrenko [27]

Answer:

Explanation:

potential energy of compressed spring

= 1/2 k d²

= 1/2 x 730 d²

= 365 d²

This energy will be given to block of mass of 1.2 kg in the form of kinetic energy .

Kinetic energy after crossing the rough patch

= 1/2 x 1.2 x 2.3²

= 3.174 J

Loss of energy

= 365 d² - 3.174  

This loss is due to negative work done by frictional force

work done by friction = friction force x width of patch

= μmg d ,   μ = coefficient of friction , m is mass of block , d is width of patch

= .44 x 1.2 x 9.8 x .05

= .2587 J

365 d² - 3.174   = .2587

365 d² = 3.4327

d² = 3.4327 / 365

= .0094

d = .097 m

= 9.7 cm

If friction increases , loss of energy increases . so to achieve same kinetic energy , d will have to be increased so that initial energy increases so compensate increased loss .

5 0
3 years ago
What is the speed of sound at the atmospheric temperature of 30°C?
12345 [234]

The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.


First, we determine how long the parcel will fall using:


s = ut + 1/2 at²


where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity.


5.5 = (0)(t) + 1/2 (9.81)(t)²

t = 1.06 seconds



A

4 0
3 years ago
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One timing problem in using fiscal policy to counter a recession is the "legislative lag" that occurs between the
natta225 [31]

<span>One timing problem in using fiscal policy to counter a recession is called the “legislative lag” it occurs between the time the time the need for fiscal action is recognized and between the time that it is taken in action.</span>

4 0
3 years ago
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