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Amanda [17]
3 years ago
15

Consider two points on the PPF: point A, at which there are 50 oranges and 100 apricots, and point B, at which there are 51 oran

ges and 98 apricots. If the economy is currently at point B, the opportunity cost of moving to point A is _________.a. 2 apricots.
b. 1 orange.
c. 98 apricots.
d. 3 oranges.
Mathematics
1 answer:
RoseWind [281]3 years ago
3 0
D 3 oranges is the answer
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Slove for x 2x+-3=-23
choli [55]

Answer:

x = -10

Step-by-step explanation:

First you have to isolate x

then you have to add 3 on the other side.

so yeahh!!

5 0
3 years ago
Name the slope of the equation y= 2/3x + 1
umka21 [38]

Answer:

Step-by-step explanation:

y=mx+b where m is the slope of the line so the slope of this line is 2/3

3 0
3 years ago
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the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:

<span>The interquartile range is the difference between the third and the first quartiles.

The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5

The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
6 0
3 years ago
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What’s the answer helpp
padilas [110]
Answer is the second option, the one that says X+1/1
8 0
3 years ago
Plz help me with this
forsale [732]

Answer:

\frac{31x}{30}

Step-by-step explanation:

Before adding we require the fractions to have a common denominator

The lowest common denominator of 2, 5 and 3 is 30, thus

\frac{15x}{15(2)} + \frac{6x}{6(5)} + \frac{10x}{10(3)}

= \frac{15x}{30} + \frac{6x}{30} + \frac{10x}{30}

Add the numerators leaving the denominator

= \frac{15x+6x+10x}{30} = \frac{31x}{30}

5 0
4 years ago
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