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Amanda [17]
3 years ago
15

Consider two points on the PPF: point A, at which there are 50 oranges and 100 apricots, and point B, at which there are 51 oran

ges and 98 apricots. If the economy is currently at point B, the opportunity cost of moving to point A is _________.a. 2 apricots.
b. 1 orange.
c. 98 apricots.
d. 3 oranges.
Mathematics
1 answer:
RoseWind [281]3 years ago
3 0
D 3 oranges is the answer
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The line x+ 2y = 9 intersects the curve xy + 18 = 0 at the points A and B. Find the coordinates of A and B.
victus00 [196]
Subtracting the second equation by 18 on both sides, we have xy=-18. Next, we divide both sides by x to get y=-18/x  Plugging that into the first equation, we have x+2(-18/x)=9. Multiplying both sides by x, we get x^2-36=9x. After that, we subtract both sides by 9x to get x^2-9x-36=0. Finding 2 numbers that add up to -9 but multiply to -36, we do a bit of guess and check to find the answers to be -12 and 3. Factoring it, we get 
x^2-12x+3x-36=x(x-12)+3(x-12)=(x+3)(x-12). To find the x values, we have to find out when 0=(x+3)(x-12). This is simple as when you multiply 0 with anything, it is 0. Therefore, x=-3 and 12. Plugging those into x=-18/y, we get x=-18/y and by multiplying y to both sides, we get xy=-18 and then  we can divide both sides by x to get -18/x=y. Plugging -3 in, we get -18/-3=6 and by plugging 12 in we get -18/12=-1.5. Therefore, our points are (-3,6) and (12, -1.5)
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A large box is packed with 6 rows of 8 boxes of dried cranberries in the bottom layer. The box is about 4 layers high. Estimate
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A fisherman uses a spring scale to weigh a tilapia fish. He records the fish weight as a kilograms and notices that the spring s
belka [17]

Answer:

k = \frac{980a}{b}

Step-by-step explanation:

Fisherman noticed a stretch in the spring = 'b' centimetres

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If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,

F = kΔx

Where k = spring constant

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F = a(9.8)

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Δx = b centimetres = 0.01b meters

Therefore, 9.8a = k(0.01b)

k = \frac{9.8a}{0.01b}

k = \frac{980a}{b}

Therefore, spring constant of the spring will be determined by the expression, k = \frac{980a}{b}

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