Answer:
constant horizontal force developed in the coupling C = 11.25KN
the friction force developed between the tires of the truck and the road during this time is 33.75KN
Explanation:
See attached file
Answer: 4.5 V
Explanation:
Given
The voltage of each cell is 1.5 V
If they are connected end to end their potential added to give a higher potential i.e. 1.5+1.5+1.5=4.5 V
Don’t still need the answers or are u done and is it on edge
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Answer:

The Required horizontal force is 230.04N
Explanation:
Since the velocity is constant so acceleration is zero; a=0
Now the horizontal force required to move the pickup is equal to the frictional force.

where:
F_{Hn} is the required Force
u is the friction coefficient
m is the mass
g is gravitational acceleration=9.8m/s^2
Eq (1)
Now, weight increases by 42% and friction coefficient decreases by 19%
New weight=(1.42*m*g) and new friction coefficient=0.81u
Eq (2)
Divide Eq(2) and Eq (1)

The Required horizontal force is 230.04N