Force that is of equal magnitude
Explanation:
What are the integers between -4 and +4?
So, If the silica cyliner of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
To estimate the operating temperature of the radiant wall heater, we need to use the equation for power radiated by the radiant wall heater.
<h3>Power radiated by the radiant wall heater</h3>
The power radiated by the radiant wall heater is given by P = εσAT⁴ where
- ε = emissivity = 1 (since we are not given),
- σ = Stefan-Boltzmann constant = 6 × 10⁻⁸ W/m²-K⁴,
- A = surface area of cylindrical wall heater = 2πrh where
- r = radius of wall heater = 6 mm = 6 × 10⁻³ m and
- h = length of heater = 0.6 m, and
- T = temperature of heater
Since P = εσAT⁴
P = εσ(2πrh)T⁴
Making T subject of the formula, we have
<h3>Temperature of heater</h3>
T = ⁴√[P/εσ(2πrh)]
Since P = 1.5 kW = 1.5 × 10³ W
Substituting the values of the variables into the equation, we have
T = ⁴√[P/εσ(2πrh)]
T = ⁴√[1.5 × 10³ W/(1 × 6 × 10⁻⁸ W/m²-K⁴ × 2π × 6 × 10⁻³ m × 0.6 m)]
T = ⁴√[1.5 × 10³ W/(43.2π × 10⁻¹¹ W/K⁴)]
T = ⁴√[1.5 × 10³ W/135.72 × 10⁻¹¹ W/K⁴)]
T = ⁴√[0.01105 × 10¹⁴ K⁴)]
T = ⁴√[1.105 × 10¹² K⁴)]
T = 1.0253 × 10³ K
T = 1025.3 K
So, If the silica cylinder of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
Learn more about temperature of radiant wall heater here:
brainly.com/question/14548124
Answer:
Explanation:
<u>Constant Acceleration Motion</u>
It's a type of motion in which the velocity of an object changes uniformly in time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
The car initially travels at vo=7.35 m/s and accelerates at a rate of during t=2.09 s.
The final velocity is:
Answer:
The maximum force that can be applied without causing the two 43- kg crates to move is 2.7KN
Explanation:
Given data
μ coefficient of friction 0.31
mass of two crates =2*43kg
=86kg
Weight of the two crates =mg
Assuming g= 9.81m/s²
W =86*9.81= 843.66N
We know that force against friction is given by
W =μR
Where
μ is coefficient of static friction
R limiting force
To solve for let's make it the subject of the formula
R= W/μ
R=843.66/0.31
R= 2721.5N
R= 2.7KN