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Likurg_2 [28]
3 years ago
14

Which equations can be used to solve for acceleration? Check all that apply.t = ​

Physics
2 answers:
alekssr [168]3 years ago
8 0
Um I would help you but I don’t see the question
lyudmila [28]3 years ago
7 0
Acc: increasing speed/ average time
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The normal is a line perpendicular to the reflecting surface at the point of incidence.
ladessa [460]

Answer:

True

Explanation:

The normal line is defined as the line which is perpendicular to the reflecting surface at the point where the incident ray meet with the reflecting surface.

The angle of incident is defined as the angle which is subtended by the incident ray with respect to the normal ray by consider the normal ray as the base line and angle is measured from the point where incident ray is incident on the reflecting surface of the mirror.

Similarly reflecting ray can be defined as the ray which is reflected after the incident of a ray and the angle subtended by the reflecting ray is measure with respect to normal ray by considering normal ray as a base line.

Therefore, the normal ray is the perpendicular line to the reflecting surface at the point of incidence.

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An engineering intern is studying the effect of temperature on the resistance of a current carrying wire. She applies a voltage
Mars2501 [29]

Answer:

I=2.80 A

Explanation:

We Know that    R =R₀(1+∝ ΔT)

                           R=R₀ (1+3.9*10⁻³ *(61-20))

                           R=R₀ (1.1599)

                           I=V/R=V/(R₀ (1.1599)

                           1.4 = V/(R₀ (1.1599)                       ∵ equation 1

                     We have to calculate I when T=-88°

                              R =R₀(1+∝ ΔT)

                             R=R₀ (1+3.9*10⁻³ *(-88-20))

                             R=R₀ (0.5788)

                             I=V/(R₀ (0.5788)                          ∵equation 2

Dividing equation 2 by equation 1

                             \frac{I}{1.4} =\frac{1.1599}{0.5788}

                            I = 2.80 A

                         

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Answer:

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