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NISA [10]
2 years ago
7

Adam uses a fixed pulley, such as the one shown below, to lift an object. Adam applies an input force to the pulley as he pulls

down to lift the object. As he does this, Adam wonders about how the pulley is helping him. How is the pulley helping Adam lift the object?
Physics
1 answer:
stira [4]2 years ago
6 0
When Adam applies a ‘pull’ force on the pulley, there is an output force that the pulley lets out, directly pulling the object with it. We cannot always pull up objects with our bear hands, no matter how much force we apply. Which is why pulleys allow us to apply the force and pulleys do the work of pulling the objects for us, since work and force come hand in hand.
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Answer:

its two valence electrons

Explanation:

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5 0
3 years ago
What are 3 criteria for acceleration?
Temka [501]

I don't think you mean 'criteria'.  I think you mean three occurrences or
observations that indicate the presence of acceleration.

They are:

-- an object is speeding up
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Any one of these changes is acceleration.

There's a single term that covers them all.  It is "change in velocity".


3 0
3 years ago
An electron, starting from rest and moving with a constant acceleration, travels 2.0 cm in 5.0 ms. What is the magnitude of this
IrinaK [193]
 <span>s=2.7 centimeters = 0.027 meters 
t=3.9 milliseconds = 0.0039 seconds 

s=(1/2)a*t^2 
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a=(2.7*2)/(0.0039)^2 
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7 0
2 years ago
In your lab group you combined salt and water. Then you compared what happens when an egg is placed in tap water versus salt wat
Anestetic [448]

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7 0
3 years ago
Read 2 more answers
Two friends are playing a version of proton golf where the hole is marked by a single proton. The first friend reads his meter,
yarga [219]

Answer:

the electric field strength on the second one is 2.67 N/C.

Explanation:

the electric fiel on the first one is:

E1 = k×q/(r^2)

r^2 = k×q/(E1)

     = (9×10^9)×(q)/(24.0)

     = 375000000q

then the electric field on the second one is:

E2 = k×q/(R^2)

we know that R = 3r

                       R^2 = 9×r^2

E2 = k×q/(9×r^2)

     = k×q/(9×375000000q)

     = k/(9×375000000)

     = (9×10^9)/(9×375000000)

     = 2.67 N/C

Therefore, the electric field strength on the second one is 2.67 N/C.

5 0
3 years ago
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