Answer:
3.0 moles.
Explanation:
- It is a stichiometry problem.
- The chemical reaction of reacting hydrogen with oxygen to produce water is:
<em>H₂ + 1/2 O₂ → H₂O.</em>
- It is clear that <em><u>1.0 mole of H₂</u></em> reacts with 0.5 mole of O₂ to produce <u><em>1.0 mole of water</em></u>.
- The ratio of the reacting hydrogen to the produced water is 1:1.
∴ The number of moles of water created from reacting 3.0 moles of hydrogen completely with excess oxygen = 3.0 moles.
Answer:
333K
Explanation:
Answer is actually 333.15, but to round it off, is 333
<u>Answer:</u> The percent composition of fluorene is 33.08 % and benzoic acid is 36.03 %.
<u>Explanation:</u>
We are given:
Mass of mixture = 544 mg
Mass of fluorene after purification = 
Mass of benzoic acid after purification = 196 mg
To calculate the percentage composition of a substance in a mixture, we use the equation:

<u>For fluorene:</u>

Hence, the percent composition of fluorene is 33.08 %
<u>For benzoic acid:</u>

Hence, the percent composition of benzoic acid is 36.03 %
Displacement, usually the method that is used to measure the volume of an irregularly shaped object.
Answer:
on N overlaps with 1s on H.
Explanation:
Hybridization of central atom generally can be found by finding the hybridization number.Hybridization number is the sum of number of lone pairs and number of sigma bonds.
If hybridization number is 2 then the central atom is sp hybridized.
If it is 3 it is
hybridized.
If it is 4 it is
hybridized and so on.
Here in
molecule there are 3 sigma bonds and one lone pair(see the figure attached).
Hence hybridization number is 4 and hence it is s
hybridized.
And in case of hydrogen atom the only electron of it resides in the 1s orbital.
Therefore
on N overlaps with 1s on H.