Answer: As sea levels rise, coastal communities will lose land and possibly see damages in infrastructure if the levels rise high enough
The very common mineral shown in the figure that is referred in this problem that is commonly a pink- to cream-colored mineral with wavy, light-colored lines and does not effervesce would be feldspar. It make up about 41 percent weight of the Earth's crust. It is a group of rocks that contains tectosilicate compounds.
Given the following choices, determine which best suits as a characteristic of a hurricane.
Answer Choices:
A. Hurricanes occur mostly inland
B. Hurricanes create widespread damage
C. Hurricanes can only last for a short amount of time
D. Hurricanes gain strength after passing overland
Best Answer: B. Hurricanes can create widespread damage.
Reason: A would not be correct since it is more of a variable, due to the fact that hurricanes usually begin near the coastlines, hurricanes are in fact capable of moving inland for atleast 100 miles before it dies down to a tropical storm or depression.
C is not correct since hurricanes can last up to a whole week which is approximately 168 hours.
D is not correct since it is another variable in which hurricanes can decrease in strength if it comes into contact with cool and dry air which is the opposite of warm and moist which it needs in order to occur.
Therefore, the best choice is B. Hurricanes can create widespread damage, hurricanes can unleash a staggering arsenal of mother nature's strength and the most damage a hurricane has caused can go up to 125 billion USD in damages.
Answer:
The molecule has a bent geometry
Explanation:
Let us look again at the principles of VSEPR theory. The shape of a molecule depends on the number of electron pairs that surround the valence shell of the central atom in the molecule.
Lone pairs distort the molecular geometry away from what is expected on the basis of VSEPR theory.
The molecule described in the question has the form AEX2. Two substituents and one lone pair form three electron domains around the central atom. The expected geometry is trigonal planar but the observed molecular geometry is bent because of the lone pairs present.
Answer:
Average atomic mass = 17.5 amu.
Explanation:
Given data:
X-17 isotope = atomic mass17.2 amu, abundance:78.99%
X-18isotope = atomic mass 18.1 amu, abundance 10.00%
X-19isotope = atomic mass:19.1 amu, abundance: 11.01%
Average atomic mass of X = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100
Average atomic mass = (78.99×17.2)+(10.00×18.1) +(11.01+ 19.1) /100
Average atomic mass = 1358.628 + 181 +210.291 / 100
Average atomic mass = 1749.919 / 100
Average atomic mass = 17.5 amu.
