Answer:
A binary covalent compound is composed of two different elements (usually nonmetals). For example, a molecule of chlorine trifluoride, ClF3 contains 1 atom of chlorine and 3 atoms of fluorine.
Rule 1. The element with the lower group number is written first in the name; the element with the higher group number is written second in the name. Exception: when the compound contains oxygen and a halogen, the name of the halogen is the first word in the name.
Rule 2. If both elements are in the same group, the element with the higher period number is written first in the name.
Rule 3. The second element in the name is named as if it were an anion, i.e., by adding the suffix -ide to the root of the element name (e.g., fluorine = F, "fluoride" = F-; sulfur = S, "sulfide" = S2-).
Rule 4. Greek prefixes are used to indicate the number of atoms of each element in the chemical formula for the compound. Exception: if the compound contains one atom of the element that is written first in the name, the prefix "mono-" is not used.
Explanation:
<u>Answer:</u> The phase change process in which solids gets converted to gases is sublimation.
<u>Explanation:</u>
For the given options:
<u>Option a:</u> Condensation
It is a type of process in which phase change occurs from gaseous state to liquid state at constant temperature.
<u>Option b:</u> Melting
It is a type of process in which phase change occurs from solid state to liquid state at constant temperature.
<u>Option c:</u> Sublimation
It is a type of process in which phase change occurs from solid state to gaseous state without passing through the liquid state at constant temperature.
<u>Option d:</u> Deposition
It is a type of process in which phase change occurs from gaseous state to solid state without passing through the liquid state at constant temperature.
Hence, the phase change process in which solids gets converted to gases is sublimation.
CO2 is Carbon Dioxide and PU is Plutonium
Answer:
q = -6464.9 kJ
Explanation:
We are given that the heat of combustion is ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.
vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³
m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g
mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol
q = −394 kJ /mol C x 16.41 mol C = -6464.9 kJ
