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3 years ago

why should the pka of a leaving groups conjugate acid be considered when performing a substitution reaction

1 answer:

7 0

<span> A : pKa values have little effect on a functional group's ability to leave. There is no need to consider this when outlining a substitution reaction. B : In order to have a substitution reaction a compound needs to a have a functional group that will serve as a good leaving group. A high pKa (pKa > 5) of a conjugate acid produces the weakest conjugate bases in a substitution reaction. C : In order to have a substitution reaction a compound needs to a have a functional group that will serve as a poor leaving group. A low pKa (pKa > 0) of a conjugate acid produces the weakest conjugate bases in a substitution reaction. D : In order to have a substitution reaction a compound needs to a have a functional group that will serve as a good leaving group. A low pKa (pKa < 0) of a conjugate acid produces the weakest conjugate bases in a substitution reaction. This favors a substitution reaction.</span>

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IgorLugansk [536]

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3 years ago

What about these questions

Oksanka [162]

Again great job! They all look correct except 20. is 3.7 due to sig fig of least precision, which you have a mark by!! You don't even need help!;) Here comes the next chemical engineer! :)

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3 years ago

What is the net ionic equation for the following? :)

I am Lyosha [343]

Answer:

1. Mg (s) + 2Na+(aq) → 2Na(s) + Mg²⁺(aq)

2. 2K(s) + Cd²⁺(aq) → 2K⁺(aq) + Cd(s)

Explanation:

The net ionic equation of a reaction express only the chemical species that are involved in the reaction:

1. Mg (s) + Na2CrO4 (aq) → 2Na + MgCrO4(aq)

The ionic equation:

Mg (s) + 2Na+(aq) + CrO4²⁻ (aq) → 2Na + Mg²⁺ + CrO4²⁻(aq)

Subtracting the ions that don't change:

2. 2K(s) + Cd(NO3)2(aq) → 2KNO3(aq) + Cd(s)

The ionic equation:

2K(s) + Cd²⁺(aq) + 2NO3⁻(aq) → 2K⁺(aq) + 2NO3⁻(aq) + Cd(s)

Subtracting the ions that don't change:

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2 years ago

Calculate the magnitude and direction (i.e., the angle with respect to the positive H-axis, measured positive as counter-clockwi

r-ruslan [8.4K]

The graphics in the attachment is part of the question, which was incomplete.

Answer: Fr = 102N and angle of approximately 11°.

Explanation: From the attachment, it is observed that from the three forces acting on M, two are perpendicular. So to find them, we have to show their x- and y- axis components. From the graph:

Fx = 70+40-10 = 100

Fy = 40-20 = 20

Now, as the forces form a triangle, the totalforce is:

Fr = $\sqrt{Fx^{2} +Fy^{2} }$

Fr = $\sqrt{10400}$

Fr = ≈ 102N

To determine the angle requested, we use:

arctg H = $\frac{Fy}{Fx}$

arctg H = $\frac{20}{100}$

H = tg 0.2 ≈ 11°.

4 0

3 years ago

If you have 30.O g of hydrogen gas burned in excess oxygen how many moles of water can you make

vladimir1956 [14]

Answer:

15 moles

Explanation:

Data given:

mass of hydrogen (H₂) = 30.0 g

amount of oxygen (O₂) = excess

moles of water = ?

Solution:

First we look to the reaction in which hydrogen react with oxygen and make (H₂O)

Reaction:

2H₂ + O₂ -----------> 2H₂O

Now look at the reaction for mole ratio

2H₂ + O₂ -----------> 2H₂O

2 mole 2 mole

So it is 2:2 mole ratio of hydrogen to water

As we Know

molar mass of H₂ = 2(1) = 2 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now convert moles to gram

2H₂ + O₂ -----------> 2H₂O

2 mole (2 g/mol) 2 mole (18 g/mol)

4 g 36 g

So,

we come to know that 4 g of hydrogen gives 36 g of water then how many grams of water will be produce by 30 grams of hydrogen.

Apply unity formula

4 g of H₂ ≅ 36 g of H₂O

30 g of H₂ ≅ X of H₂O

Do cross multiplication

X of H₂O = 30 g x 36 g / 4 g

X of H₂O = 270 g

Now convert grams of H₂O into moles

No. of moles = mass in grams/molar mass

Put values in above formula

No. of moles = 270 g / 18 (g/mol)

No. of moles = 15 mol

so 30 gram of hydrogen produce 15 mol of water.

5 0

3 years ago