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3 years ago

why should the pka of a leaving groups conjugate acid be considered when performing a substitution reaction

1 answer:

7 0

A : pKa values have little effect on a functional group's ability to leave. There is no need to consider this when outlining a substitution reaction. B : In order to have a substitution reaction a compound needs to a have a functional group that will serve as a good leaving group. A high pKa (pKa > 5) of a conjugate acid produces the weakest conjugate bases in a substitution reaction. C : In order to have a substitution reaction a compound needs to a have a functional group that will serve as a poor leaving group. A low pKa (pKa > 0) of a conjugate acid produces the weakest conjugate bases in a substitution reaction. D : In order to have a substitution reaction a compound needs to a have a functional group that will serve as a good leaving group. A low pKa (pKa < 0) of a conjugate acid produces the weakest conjugate bases in a substitution reaction. This favors a substitution reaction.

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Anni [7]

Hello!

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We have the following data:

mo (initial mass) = 20 g

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x (number of periods elapsed) = ?

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Let's find the number of periods elapsed (x), let us see:

$m = \dfrac{m_o}{2^x}$

$5 = \dfrac{20}{2^x}$

$2^x = \dfrac{20}{5}$

$2^x = 4$

$2^x = 2^2$

$\boxed{x = 2}$

Now, let's find the half-life (P) of the radioactive sample, let's see:

$T = x*P$

$8 = 2*P$

$2\:P = 8$

$P = \dfrac{8}{2}$

$\boxed{\boxed{P = 4\:minutes}}\Longleftarrow(Half-Life)\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

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Strike441 [17]

Answer:

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