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vampirchik [111]
3 years ago
6

why should the pka of a leaving groups conjugate acid be considered when performing a substitution reaction

Chemistry
1 answer:
NeTakaya3 years ago
7 0
<span> A : pKa values have little effect on a functional group's ability to leave. There is no need to consider this when outlining a substitution reaction. B : In order to have a substitution reaction a compound needs to a have a functional group that will serve as a good leaving group. A high pKa (pKa > 5) of a conjugate acid produces the weakest conjugate bases in a substitution reaction. C : In order to have a substitution reaction a compound needs to a have a functional group that will serve as a poor leaving group. A low pKa (pKa > 0) of a conjugate acid produces the weakest conjugate bases in a substitution reaction. D : In order to have a substitution reaction a compound needs to a have a functional group that will serve as a good leaving group. A low pKa (pKa < 0) of a conjugate acid produces the weakest conjugate bases in a substitution reaction. This favors a substitution reaction.</span>
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How many moles of lithium metal would need to react with excess oxygen gas to produce 4 moles of lithium oxide in the following
irina1246 [14]

8 moles of Lithium are needed.

3 0
3 years ago
What us the % composition of oxygen (O) in iron (III) hydroxide, Fe(OH)<br> 3?
S_A_V [24]

Answer:

44.91% of Oxygen in Iron (III) hydroxide

Explanation:

To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:

<em>Molar mass Oxygen / molar mass Fe(OH)3 * 100</em>

<em />

<em>Molar mass Fe(OH)3 and oxygen:</em>

1Fe = 55.845g/mol*1 = 55.845

3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen

3H = 1.008g/mol*3 = 3.024

55.845 + 48.00 + 3.024 =

106.869g/mol is molar mass of Fe(OH)3

% Composition of oxygen is:

48.00g/mol / 106.869g/mol * 100 =

<h3>44.91% of Oxygen in Iron (III) hydroxide</h3>
7 0
2 years ago
2. A chemical analysis of a sample provides the following elemental data:
Vadim26 [7]

Answer:

C3 H6 O2

Explanation:

first divide their mass by their respective molar mass, we get:

30.4 moles of C

61.2 moles of H

20.25 moles of O

now divide everyone by the smallest one of them then we get

C= 1.5

H= 3

O= 1

since our answer of C is not near to any whole number so we will multiply all of them by 2

so,

C3 H6 O2 is our answer

3 0
1 year ago
A 2.50 g sample of solid sodium hydroxide is added to 55.0 mL of 25 °C water in a foam cup (insulated from the environment) and
zlopas [31]

Answer:

37.1°C.

Explanation:

  • Firstly, we need to calculate the amount of heat (Q) released through this reaction:

<em>∵ ΔHsoln = Q/n</em>

no. of moles (n) of NaOH = mass/molar mass = (2.5 g)/(40 g/mol) = 0.0625 mol.

<em>The negative sign of ΔHsoln indicates that the reaction is exothermic.</em>

∴ Q = (n)(ΔHsoln) = (0.0625 mol)(44.51 kJ/mol) = 2.78 kJ.

  • We can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released to water (Q = 2781.87 J).

m is the mass of water (m = 55.0 g, suppose density of water = 1.0 g/mL).

c is the specific heat capacity of water (c = 4.18 J/g.°C).

ΔT is the difference in T (ΔT = final temperature - initial temperature = final temperature - 25°C).

∴ (2781.87 J) = (55.0 g)(4.18 J/g.°C)(final temperature - 25°C)

∴ (final temperature - 25°C) = (2781.87 J)/(55.0 g)(4.18 J/g.°C) = 12.1.

<em>∴ final temperature = 25°C + 12.1 = 37.1°C.</em>

6 0
2 years ago
Which has the greatest mass, box of rocks box of paperclips or empty box
olga nikolaevna [1]
The density of an ordinay rock is close to 3 g/cm^3 wihle the density of the paper clips is close to 8 g/cm^3 (the density of steel), then equal apparent volumes (same box) will contain different mass, being of course the mass of the box with paper clips much higher than that of the box with rocks.
7 0
3 years ago
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