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vladimir1956 [14]
3 years ago
10

Someone please help will mark as brainliest

Chemistry
1 answer:
sveticcg [70]3 years ago
7 0
I would think 38n uugghhgffryhn
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1. A solution is made by mixing 50mL of 2.0M K2HPO4 and 25mL of 2.0M KH2PO4. The solution is diluted to a final volume of 200mL.
Kazeer [188]

Answer:

The pH of the final solution is 7.15

Explanation:

50 mL of 2.0 M of K_2HPO_4 and 25 mL of 2.0 M of KH_2PO_4 were mixed to make a solution

Final volume of the solution after dilution = 200 mL

Final concentration of K_2HPO_4, [K_2HPO_4] = \frac{50 mL\times 2 M}{200 mL} = 0.5 M

Final concentration ofKH_2PO_4, [KH_2PO_4] = \frac{25 mL\times 2 M}{200 mL} = 0.25 M

We use Hasselbach- Henderson equation:

pH = pK_a+ log \frac{[salt]}{[acid]}pka of KH_2PO_4 = 6.85

Substituting the values:

pH = 6.85+ log \frac{0.5}{0.25}pH = 6.85+ log 2pH = 6.85+ 0.3 = 7.15

Therfore,  the pH of the final solution is 7.15

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